Answer:
First, solve for two points as an equation instead of an inequality to find the boundary line for the inequality.
For:
x
=
0
y
=
0
+
5
y
=
5
Or
(
0
,
5
)
For:
x
=
−
2
y
=
−
2
+
5
y
=
3
Or
(
−
2
,
3
)
We can now plot the two points on the coordinate plane and draw a line through the points to mark the boundary of the inequality.
The boundary line will be solid because the inequality operator contains an "or equal to" clause.
graph{(x^2+(y-5)^2-0.125)((x+2)^2+(y-3)^2-0.125)(y-x-5)=0 [-20, 20, -10, 10]}
Now, we can shade the left side of the line.
graph{(y-x-5) >= 0 [-20, 20, -10, 10]}
Answer:
Hi what language is that I don't know that language so I cannot answer your question
Answer:
Step-by-step explanation:
hope this helps you.
Answer:
CV for statistics exam = 15%
CV for calculus exam = 19%
Since the CV for calculus exam is higher, it has a greater spread relative to the mean than the statistics exam.
Step-by-step explanation:
To find coefficient variation we use the formula:
CV = (SD/mean) * 100
CV for the statistics exam:
where; SD= 5
mean= 75
CV = ( 5/75) *100
= 0.15 or 15%
CV for calculus exam
SD = 11
Mean= 58
CV= (11 /58) * 100
= 0.19 or 19%
