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QveST [7]
3 years ago
11

17.The diameter of a circle has endpoints P(–7, –10) and Q(3, 2).

Mathematics
1 answer:
ser-zykov [4K]3 years ago
7 0
A.) (-2,-4)
(7+3)/2=5, (10+2)/2=6
(-7+5,-10+6)
(-2,-4)
b.)r^2=244
10^2+12^2=244
r=2(61)^(1/2)
c.)(x+2)^2+(y+4)^2=244
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zvonat [6]

Answer:

ΔGFE≈ΔJKL

Step-by-step explanation:

5 0
2 years ago
your 5-year loan of $14 000 is at 4.3% compounded annually. How much will you have paid in total for your loan?
kogti [31]

Answer:

$17, 280.00

Step-by-step explanation:

A= P(1+r)^t

A= 14000(1+0.043)^5

A= 17, 280

4 0
3 years ago
The volume of a right cone is 17287 units³. If its circumference measures 247 units,
Nikolay [14]

The height of the right cone is 10.68 unit

<h3>What is Volume ?</h3>

Volume is defined as the space occupied by a three dimensional object.

Volume of a right cone is given  by

V = π r²h/3

C = 2 π r

r = 247/2 π

3 * 17287 =  π  r²h

3 * 17287 =  π *(247/2 π )²h

h = 51861 *π *4/61009

h = 10.68 unit

Therefore the height of the right cone is 10.68 unit.

To know more about Volume

brainly.com/question/1578538

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7 0
2 years ago
An insurance office buys paper by the ream, 500 sheets, for use in the copier, fax, and printer. Each ream lasts an average of 4
postnew [5]

Answer:

a) the probability that the next ream out- lasts the present one by more than 2 days is 0.0787

b) the number of reams that must be purchased is 19

Step-by-step explanation:

Given the data in the question;

Lets X₁ and X₂ be the two random variables that represents the first and second ream lasts

given that both random variables follow normal distribution with mean 4 and standard deviation 1.

a)

Find the probability that the next ream out- lasts the present one by more than 2 days.

P( X₂  - X₁ > 2 ) = P( [(X₂  - X₁ - E(X₂  - X₁)) / √(V(X₂  - X₁)] > [ (2-E(X₂  - X₁))/√(V(X₂  - X₁) ]

= 1 - P( Z ≤ [2-(μ₂  - μ₁)] / [√( V(X₂) + V(X₁) ) ] )

= 1 - P( Z ≤ [2-(4  - 4)] / [√( 1 + 1 )] )

= 1 - P = ( Z ≤ 2 / √2 )

= 1 - p( Z ≤ 1.4142 )

from excel; p( Z ≤ 1.41 ) = 0.9213

P( X₂  - X₁ > 2 ) = 1 - 0.9213

P( X₂  - X₁ > 2 ) = 0.0787

Therefore, the probability that the next ream out- lasts the present one by more than 2 days is 0.0787

b)

How many reams must be purchased if they are to last at least 60 days with probability at least 80%

total value is 4n

standard deviation is nσ

so

P(nX ≥ 60 ) = 0.80

P( nX-nμ /nσ  ≥  60-nμ/nσ) = 0.80

P( Z ≥  60-4n/n) = 0.80

1 - P( Z ≥  60-4n/n) = 0.80

P( Z < z ) = 0.20

now since z = 60-4n/n

from standard normal table

critical value of z corresponding to cumulative area of 0.20 is -0.841

so

z = - 0.841

60-4n/n =  -0.841

60 - 4n =  -0.841n

60 = -0.841n + 4n

60 = 3.159n

n = 60 / 3.159

n = 18.99 ≈ 19

Therefore, the number of reams that must be purchased is 19

5 0
2 years ago
Please help me solve this
Leokris [45]

Answer:

x - 6 >  - 2 \\ x  >   - 2 + 6 \\ x > 4

Step-by-step explanation:

So, the answer is the first one

4 0
2 years ago
Read 2 more answers
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