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3 years ago

the hypotenuse of a right triangle is 15 cm and the shorter leg is 9cm find the length of the other leg

Mathematics

2 answers:

DanielleElmas [232]3 years ago

5 0

Answer:

12 cm is your answer

Step-by-step explanation:

Use the equation: a² + b² = c² , in which c is the hypotenuse, and a & b are the other sides.

Note that the hypotenuse is 15, and the shorter leg is 9 cm. Plug in the corresponding numbers into the corresponding variables

a² + (9)² = (15)²

Simplify. First, solve for the solvable squares

a² + 81 = 225

Isolate the variable a. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS. First, subtract 81 from both sides:

a² + 81 (-81) = 225 (-81)

a² = 225 - 81

a² = 144

Isolate the variable a. Root both sides.

√(a²) = √(144)

a = √144 = √(12 * 12) = 12

a = 12

12 cm is your answer

vladimir2022 [97]3 years ago

3 0

Answer:

Step-by-step explanation:

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Step-by-step explanation:

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vfiekz [6]

Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

In a figure, OB is the radius of a big semicircle and XB is the radius of the small semicircle. Given that OX = 14 cm, Calculate

oee [108]

Answer:

perimeter of the shaded region = 88 +44+28 =160 cm

Step-by-step explanation:

perimeter of shaded region = length AO + arc OB + arc AB

length AO = radius of bigger circle

radius of bigger circle = OX + OB = 2×radius of smaller circle = 2×14 cm = 28 cm

therefore AO = 28 cm

length of arc oB= half of circumference of smaller circle = $\pi$ ×14 = 44 cm

length of arc ab = half of circumference of bigger circle = $\pi$ ×28 = $\frac{22}{7}$ ×28= 88

therefore perimeter of the shaded region = 88 +44+28 =160 cm

area of the shaded region = half of area of bigger circle - half of area of smaller circle

= $\frac{1}{2} \pi 28^{2} -\frac{1}{2} \pi 14^{2}$

= $\frac{\pi }{2} (28^{2} -14^{2} )$

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dezoksy [38]

Answer:

(9(3)+1)/3÷(2(4)+3)/4

28/3÷11/4

28/3×4/11

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3 years ago

How do you go about doing this surface area problem?

hammer [34]

Break it down into 2-Dimensional shapes. Then add the areas together.

From the picture you can see;
front & back rectangles are 2*(4 x 8) = 64 m²
2 side rectangles are 2*(4 x 12) = 56 m²
2 triangular front & back pieces are (1/2)*8*3 = 12 m²
2 roof rectangles are 2*(5 x 12) = 120 m²

total Surface area = 64 m² + 56 m² + 12 m² + 120 m²
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From the picture you can see;
Rectangular box volume is 4 x 8 x 12 = 384 m³
Triangular roof volume is area of front triangle multiplied through the length. (1/2)*8*3* 12 = 144 m³

Total volume = 384 m³ + 144 m³
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3 years ago