Answer:
Since the computed value of t= 0.833 does not fall in the critical region we therefore do not reject H0 and may conclude that population mean is greater than 160. Or the sample comes from population with mean of 165.
Step-by-step explanation:
- State the null and alternative hypothesis as
H0: μ= 160 against the claim Ha :μ ≠160
Sample mean = x`= 165
Sample standard deviation= Sd= 12
2. The test statistic to use is
t= x`-μ/sd/√n
which if H0 is true , has t distribution with n-1 = 36-1= 35 degrees of freedom
3. The critical region is t< t (0.025(35)= 2.0306
t= x`-μ/sd/√n
4. t = (165-160)/[12/√(36)] = 5/[6] = 0.833
5. Since the computed value of t= 0.833 does not fall in the critical region we therefore do not reject H0 and may conclude that population mean is greater than 160. Or the sample comes from population with mean of 165.
Now
6. The p-value is 0 .410326 for t= 0.8333 with 35 degrees of freedom.
Answer:
x=0
x=6
x=-1
Step-by-step explanation:
x(x^2-5x-6)
x(x-6)(x+1)
x=0
x=6
x=-1
Answer:
see explanation
Step-by-step explanation:
(5)
Since ∠EBA = 90° then ∠ABD = 90° ( straight angle ) and
∠ABC + ∠CBD = ∠ABD, that is
2x + 3x - 10 = 90, simplifying
5x - 10 = 90 ( add 10 to both sides )
5x = 100 ( divide both sides by 5 )
x = 20, thus
∠ABC = 2x = 2 × 20 = 40°
∠CBD = 3x - 10 = (3 × 20) - 10 = 60 - 10 = 50°
(6)
4x - 18 = 3x + 7 ( vertical angles are congruent )
Subtract 3x from both sides
x - 18 = 7 ( add 18 to both sides )
x = 25
7y = 5y + 28 ( vertical angles are congruent )
Subtract 5y from both sides
2y = 28 ( divide both sides by 2 )
y = 14
Answer:
y= 5x+2
Explanation:
slope is 5 and the y-intercept is 2.
Answer: X=2 Y=-6
Step-by-step explanation: