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grandymaker [24]

3 years ago

15

Scientists in Florida are measuring the masses of sea turtles as they hatch. They create a line graph and plots the masses of 18

turtles, rounded to the nearest 1/4 of an ounce.

1 answer:

NeTakaya3 years ago

8 0

Answer:

36 3/4

Step-by-step explanation:

12 1/4 + 12 1/4 + 12 1/4 = 36 3/4 :)

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Find the perimeter of rectangle ABCD. That’s the full photo. Only half of the rectangle is provided. You should be able to solve

riadik2000 [5.3K]

Answer:

170°

Step-by-step explanation:

We can already see that measure ∠AD is equal to 85

A square has two halves, so this square will be added.

We will have to add 85 + 85 which equals 170°

5 0

3 years ago

How can I solve this math equation?

alukav5142 [94]

Answer:

Graphing

Step-by-step explanation:

1) You can graph this equation by using y=mx+b. You can replace that equation with y=3x-1.

M=3

X=x

B=-1

On a graph you would down 1 since it's negative and make a point. Then you would put a 1 under the 3 to make it a fraction. 3/1. Then you would divide 1 by 3 (1 ÷ 3). Then you would go to the right 0.33 because it's positive, and the up 1. Then you would make a second point.

This would only give you one line which wouldn't give you an intersection.

6 0

3 years ago

Read 2 more answers

a rectangle has an area of 1/6 squar centimeters and a length of 1.5 centimeters what is the width and the perimeter

Alex73 [517]

<span>

(1/6)/ 1.5 =
(1/6)/(15/10)=
1/6*10/15=10/90=1/9 width</span>

3 0

3 years ago

Write two expressions to show w increased by 4. Then, draw models to prove that both expressions represent the same thing.

Vinil7 [7]

Answer:Answer:

w + 4 and 4 + w

Step-by-step explanation:

Given phrase,

w is increased by 4,

That is, w + 4

By the commutative property of addition,

The expression would be,

4 + w

For drawing a model that shows w + 4

Take two boxes in which first shows w and second shows 4 and add them,

Similarly, for showing 4 + w, take first box that shows 4 and second box that shows w then add them.

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

A random sample of soil specimens was obtained, and the amount of organic matter (%) in the soil was determined for each specime

Shalnov [3]

Answer:

We conclude that the true average percentage of organic matter in such soil is different from 3%.

Step-by-step explanation:

We are given that the values of the sample mean and sample standard deviation are 2.481 and 1.616, respectively.

Suppose we know the population distribution is normal, we have to test the hypothesis that does this data suggest that the true average percentage of organic matter in such soil is something other than 3%.

<em>Let </em> $\mu$ <em> = true average percentage of organic matter in such soil</em>

SO, <u>Null Hypothesis</u>, $H_0$ : $\mu$ = 3% {means that the true average percentage of organic matter in such soil is equal to 3%}

<u>Alternate Hypothesis</u>, $H_A$ : $\mu \neq$ 3% {means that the true average percentage of organic matter in such soil is different than 3%}

The test statistics that will be used here is <u>One-sample t test statistics</u> because we don't know about the population standard deviation;

T.S. = $\frac{\bar X -\mu}{{\frac{s}{\sqrt{n} } } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean amount of organic matter = 2.481%

s = sample standard deviation = 1.616%

n = sample of soil specimens = 30

So, <u><em>test statistics</em></u> = $\frac{0.02481-0.03}{{\frac{0.01616}{\sqrt{30} } } }$ ~ $t_2_9$

= -1.759

<u></u>

<u>Now, P-value of the test statistics is given by;</u>

P-value = P( $t_2_9$ > -1.759) = <u>0.046</u> or 4.6%

If the P-value of test statistics is more than the level of significance, then we will not reject our null hypothesis as it will not fall in the rejection region.

If the P-value of test statistics is less than the level of significance, then we will reject our null hypothesis as it will fall in the rejection region.

<em>Now, here the P-value is 0.046 which is clearly smaller than the level of significance of 0.05 (for two-tailed test), so we will reject our null hypothesis as it will fall in the rejection region.</em>

Therefore, we conclude that the true average percentage of organic matter in such soil is different from 3%.

3 0

3 years ago