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daser333 [38]
3 years ago
15

Given that 2^x = 7, find the value of 4^x-1.

Mathematics
1 answer:
Helga [31]3 years ago
4 0

4=2^2\\\\4^x=(2^2)^x=(2^x)^2=7^2=49\\\\4^x-1=49-1=48


If\ is\ 4^{x-1},\ then\\\\4^{x-1}=\dfrac{4^x}{4}=\dfrac{49}{4}=12\frac{1}{4}

Used:\\\dfrac{a^n}{a^m}=a^{n-m}

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