Find one value of xxx that is a solution to the equation: (2x+3)^2-4(2x+3)-12=0(2x+3) 2 −4(2x+3)−12=0
1 answer:
Answer:
x = -5/2 or 3/2
Step-by-step explanation:
If we let z = 2x+3, the equation can be written ...
... z² -4z -12 = 0
and can be factored as
... (z -6)(z +2) = 0
Then the solutions are z = -2, z = 6.
This means the values of x that are solutions are ...
... 2x +3 = {-2, 6} . . . . work with both possibilities at once
... 2x = {-5, 3} . . . . . . . subtract 3
... x = {-5/2, 3/2} . . . . .divide by 2
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Answer:
Absolute minimum = 1.414
Absolute maximum = 2.828
Step-by-step explanation:
For absolute minimum we take the minimum values of and
.
Plugging in the minimum values in the function.
Absolute minimum value will be always positive.
∴ Absolute minimum = 1.414
For absolute maximum we take the maximum values of and
.
Plugging in the maximum values in the function.
Absolute maximum value will be always positive.
∴ Absolute maximum = 2.828