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uranmaximum [27]
3 years ago
10

Find one value of xxx that is a solution to the equation: (2x+3)^2-4(2x+3)-12=0(2x+3) 2 −4(2x+3)−12=0

Mathematics
1 answer:
strojnjashka [21]3 years ago
4 0

Answer:

x = -5/2 or 3/2

Step-by-step explanation:

If we let z = 2x+3, the equation can be written ...

... z² -4z -12 = 0

and can be factored as

... (z -6)(z +2) = 0

Then the solutions are z = -2, z = 6.

This means the values of x that are solutions are ...

... 2x +3 = {-2, 6} . . . . work with both possibilities at once

... 2x = {-5, 3} . . . . . . . subtract 3

... x = {-5/2, 3/2} . . . . .divide by 2

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masya89 [10]

Answer:

D

Step-by-step explanation:

Either try all the numbers and see which ones work or do the following.

Times both sides by 2x-5.

3=x(2x-5)=2x^2-5x

Rearrange and solve the quadratic. I will factorise.

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3 years ago
The thumb length of fully grown females of a certain type of frog is normally distributed with a mean of 8.59 mm and a standard
PilotLPTM [1.2K]

Answer:

21.77% probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 8.59, \sigma = 0.63

Calculate the probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.

This is 1 subtracted by the pvalue of Z when X = 9.08. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{9.08 - 8.59}{0.63}

Z = 0.78

Z = 0.78 has a pvalue of 0.7823

1 - 0.7823 = 0.2177

21.77% probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.

8 0
3 years ago
Does the table represent a linear relationship (3,15) (9,45) (21,105) why or why not?
Tasya [4]
Sysydystistisitw58w58w693636e59e5969e69
7 0
2 years ago
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