1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
uranmaximum [27]
3 years ago
10

Find one value of xxx that is a solution to the equation: (2x+3)^2-4(2x+3)-12=0(2x+3) 2 −4(2x+3)−12=0

Mathematics
1 answer:
strojnjashka [21]3 years ago
4 0

Answer:

x = -5/2 or 3/2

Step-by-step explanation:

If we let z = 2x+3, the equation can be written ...

... z² -4z -12 = 0

and can be factored as

... (z -6)(z +2) = 0

Then the solutions are z = -2, z = 6.

This means the values of x that are solutions are ...

... 2x +3 = {-2, 6} . . . . work with both possibilities at once

... 2x = {-5, 3} . . . . . . . subtract 3

... x = {-5/2, 3/2} . . . . .divide by 2

You might be interested in
Subtract: 8.2 - 4.63 <br> A) 3.47 <br> B) 3.57<br> C) 3.63<br> D). 4.63
Agata [3.3K]

Answer:

the answer is B)3.57

you line up the decimals

8.20-

4.63

subtract down

Step-by-step explanation:

5 0
3 years ago
Solve the inequality:
olya-2409 [2.1K]

Answer:

8 - 2x <4 gives us x>2

|x-8| >22 gives us (-inf, -14) and (30,inf)

|x+5| < 4 gives us (-9,-1)

Step-by-step explanation:

Inequalities differs from equalities in that they return a range of values for x and not a single value (case of equalities)

The first one

8 - 2x <4 if you subtract every side 8, you will get -2x<-4

Next divide every side with -2, since its a negative number you have to change the orientation of the inequaiity, thus we have x>4/2, x>2

The second

|x-8| >22, it has to be treated as this. -22>x-2>22 which can be treated as two single inequalities, -22>x-8, and the other, x-8>22. The fist gives you x<-14, and the other x>30, two non intercepting ranges, so your range will be (-inf, -14) and (30, inf)

The third

|x+5| < 4 if you apply the same steps from above, you will have the following  -4<x+5<4 This results in two intercepting ranges, giving you the range (-9,-1)

4 0
4 years ago
The Han dynasty lasted from 206 B.C. to 9 A.D. How many years did the dynasty last?
cricket20 [7]

Answer:

The Han dynasty last was, 215 years

Step-by-step explanation:

Given statement: The Han dynasty lasted from 206 B.C. to 9 A.D.

To find how many years did the dynasty last.

B.C. represents Before Christ

A.D. represents After Death

To find the difference between two dates,

  • When the endings are the same you subtract
  • When they are different you add

You can see that the endings in the given 206 B.C. and 9 A.D. are B.C. and A.D. are different.

Just add these 206 and 9 we get;

206 + 9 = 215 years

Therefore, 215 years did the Han dynasty last.


4 0
3 years ago
Which two integers are 7 units away from the number 0 an a number line ?
Anarel [89]
4. The answer is -7 and 7. Start at 0 and count to the left. That’s -7. Then to the right it’s 7
5 0
3 years ago
Read 2 more answers
PLEASE ANSWER ASAP !!!
Zigmanuir [339]

Answer:

the midpoint would be:(0,5)

Step-by-step explanation:

3 0
3 years ago
Other questions:
  • Reduce the fraction 20/100.
    12·1 answer
  • Form the union for the following sets.
    9·2 answers
  • What is the answer a,b,c,d? I need help
    13·1 answer
  • PLEASE!!! SOMETHING WHITE THAT INSIDE HAS A FLOWER. IT MAY BE A SYMBOL. ITS A RIDDLE.
    14·1 answer
  • Help me please thank you
    8·1 answer
  • The number of hours of​ daylight, H, on day t of any given year​ (on January​ 1, tequals​1) in a particular city can be modeled
    7·1 answer
  • Q10. Use substitution. What is the solution of the system of equations?
    6·1 answer
  • Write a rule for g described by the transformation of the graph of f...
    12·1 answer
  • The area of a rectangle is x 2 – 3x – 28. If the width is (x – 7), what is the length? (hint: it is a binomial)
    8·1 answer
  • PLEASE HELP ME
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!