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4 years ago

14

The perimeter of a rectangle is given by P equals 2 l plus 2 w. Find the width of a rectangle whose length is 35 and perimeter i

s 84 in.

1 answer:

maks197457 [2]4 years ago

5 0

2l + 2w = P
l = 35, P = 84, w=?

2*35 + 2*w = 84
70 + 2w = 84
2w = 84 - 70
2w = 14
w = 14/2
w = 7 in

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$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{x^{n+1}}{2(n+1)-1}}{\frac{x^n}{2n-1}}\right|=|x|\lim_{n\to\infty}\frac{\frac1{2n+1}}{\frac1{2n-1}}=|x|-\lim_{n\to\infty}\frac{2n-1}{2n+1}=|x|$

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