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rjkz [21]
3 years ago
14

The perimeter of a rectangle is given by P equals 2 l plus 2 w. Find the width of a rectangle whose length is 35 and perimeter i

s 84 in.
Mathematics
1 answer:
maks197457 [2]3 years ago
5 0
2l + 2w = P
l = 35,  P = 84,  w=?

2*35 + 2*w = 84
70 + 2w = 84
2w = 84 - 70
2w = 14
w = 14/2
w = 7 in
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Afla un numar,stiind ca: a)jumatatea treimii lui este 25; b)sfertul jumatatii lui este 48; c)treimea sfertului sau,marita cu 17
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(b) 384

(c)  84

(d) 261

(e ) 480

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(a)

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\dfrac{1}{2}\times(\dfrac{1}{3}a)=25\\\\\dfrca{1}{2\times3}a=25\\\\\dfrac{1}{6}\times a=25\\\\a=25\times6\\\\a=150    

Hence, the number is 150.

(b)

Let 'b' be  the number such that the quarter of his half is 48 i.e.

\dfrac{1}{4}(\dfrac{1}{2}b)=48\\\\\dfrac{1}{8}b=48\\\\b=48\times8\\\\b=384

Hence the number is 384.

(c)

Let 'c' be the number such that the third quarter or, increased by 17 is 80.

\dfrac{3}{4}c+17=80\\\\\dfrac{3}{4}c=80-17\\\\\dfrac{3}{4}c=63\\\\c=\dfrac{63\times4}{3}\\\\c=\dfrac{252}{3}\\\\c=84

Hence, the number is 84.

(d)

Let 'd'  be the number such that its triplet, reduced by 28 is 755

3d-28=755\\\\3d=755+28=783\\\\d=\dfrac{783}{3}\\\\d=261

Hence the number is 261.

(e  

Let 'e' be the number such that double his third, increased by 80 is 400.

\\2\dfrac{1}{3}e+80=400\\\\\dfrac{2}{3}e=400-80=320\\\\e=\dfrac{320\times 3}{2}\\\\e=\dfrac{960}{2}\\\\e=480

Hence, the value of the number is 480.


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