Answer:
C, D
Step-by-step explanation:
This equation can be solved any of several ways. One that doesn't require much thought is using the quadratic formula.
For ax² +bx +c = 0, the solutions are ...
In the given equation, a=2, b=11, c=5, so this becomes ...
The solutions are ...
C. x = -5
D. x = -1/2
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My personal favorite is using a graphing calculator. The solutions are the x-intercepts of the expression on the left. That is, where its value is zero, as the equation says.
Answer:
s(x) is t(x) ...
Domain and Range
Step-by-step explanation:
t(x) is the square root function reflected across the y-axis and compressed horizontally by a factor of 2. That is, in f(x) = √x, the x has been replaced by -2x.
s(x) has the function t(x) <em>reflected back across the y-axis</em> and compressed horizontally by another factor of 2. It is also <em>translated downward by 5 units</em>, so that its origin (vertex) is at (0, -5).
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The graph shows you the domain and range of s(x). The domain is all numbers to the right of x=0, including x=0. That is ...
domain: x ≥ 0
The range is all numbers -5 or above:
range: y ≥ -5
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For t(x), the argument of the square root function must not be negative, which means the value of x cannot be positive.
domain: x ≤ 0
For non-negative values of radicand, the t(x) function will have non-negative values. So, the range is ...
range: y ≥ 0
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<em>Comment on solving problems like this</em>
Your graphing calculator can be your friend.
