Question

Graph the linear equation find three points that solves the equation 2y=5x+11

Answer 1

Answer:

Attachment

Step-by-step explanation:

Convert to the slope-intercept form (y = mx + b):

$2y=5x+11$             divide both sides by 2

$\dfrac{2y}{2}=\dfrac{5x}{2}+\dfrac{11}{2}\\\\y=\dfrac{5}{2}x+\dfrac{11}{2}$

We choose any three x values ​​and calculate the y value:

for x = -1

$y=\dfrac{5}{2}(-1)+\dfrac{11}{2}=-\dfrac{5}{2}+\dfrac{11}{2}=\dfrac{6}{2}=3\to A(-1,\ 3)$

for x = 1

$y=\dfrac{5}{2}(1)+\dfrac{11}{2}=\dfrac{5}{2}+\dfrac{11}{2}=\dfrac{16}{2}=8\to B(1,\ 8)$

for x = -3

$y=\dfrac{5}{2}(-3)+\dfrac{11}{2}=-\dfrac{15}{2}+\dfrac{11}{2}=-\dfrac{4}{2}=-2\to C(-3,\ -2)$

Mark the points on the coordinate plane and draw a line through the given points.