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3 years ago

15

Jayden used 20 color ties to make a design above his stove 15 out of 20 of his tires were green what is an equivalent fraction f

or the green tie

1 answer:

skad [1K]3 years ago

3 0

Answer:

3/4

Step-by-step explanation:

15.20 simplified = 3/4

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How many times greater is 7 x 10^6 than 4.5 x 10^-1

kipiarov [429]

Let us assume that : 7 × 10⁶ is P times Greater than 4.5 × 10⁻¹

It means when we Multiply P with 4.5 × 10⁻¹, We should get 7 × 10⁶

⇒ (P × 4.5 × 10⁻¹) = 7 × 10⁶

$\mathsf{\implies P = (\dfrac{7 \times 10^6}{4.5 \times 10^-^1})}$

$\mathsf{\implies P = 1.56 \times 10^7}$

⇒ 7 × 10⁶ is 1.56 × 10⁷ times Greater than 4.5 × 10⁻¹

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3 years ago

What is a simplest way to find out x

konstantin123 [22]

Answer:

You should start with a simple equation. And remember- practice makes perfect.

The basic algebraic equation involves simple addition or subtraction with one unknown quantity, such as 2 + x = 7.

1. Subtract 2 from both sides: 2 - 2 + x = 7 - 2.

2. Simplify the equation by doing the math: 2-2+x=7-2=0+x=5, or x = 5.

3. Check your work by substituting the answer, 5, into the equation for x.

The correct answer is x=5.

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3 years ago

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Find the measure of ∠b.

luda_lava [24]

Answer:

B. 38°

Step-by-step explanation:

The angles of a triangle add up to 180.

So, 62 + 80 + b will add up to 180.

First, we add 62 =80, which gives us 142.

The we subtract 142 from 180, which gives us 38.

6 0

3 years ago

Hello i need some help!

murzikaleks [220]

Answer:

3×2 + 3×-b

Step-by-step explanation:

$3(2-b)\\= 3\times 2 + 3\times (-b)\\\\= 6 -3b$

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3 years ago

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A university found that 20% of its students withdraw without completing the introductory statistics course. Assume that 20 stude

bulgar [2K]

Answer:

a) 20.61%

b) 21.82%

c) 42.36%

d) 4 withdrawals

Step-by-step explanation:

This situation can be modeled with a binomial distribution, where p = probability of “success” (completing the course) equals 80% = 0.8 and the probability of “failure” (withdrawing) equals 0.2.

So, the probability of exactly k withdrawals in 20 cases is given by

$\large P(20;k)=\binom{20}{k}(0.2)^k(0.8)^{20-k}$

a)

We are looking for

P(0;20)+P(0;1)+P(0;2) =

$\large \binom{20}{0}(0.2)^0(0.8)^{20}+\binom{20}{1}(0.2)^1(0.8)^{19}+\binom{20}{2}(0.2)^2(0.8)^{18}=$

0.0115292150460685 + 0.0576460752303424 + 0.136909428672063 = 0.206084718948474≅ 0.2061 or 20.61%

b)

Here we want P(20;4)

$\large P(20;4)=\binom{20}{4}(0.2)^4(0.8)^{16}=0.218199402\approx 0.2182=21.82\%$

c)

Here we need

$\large \sum_{k=4}^{20}P(20;k)=1-\sum_{k=1}^{3}P(20;k)$

But we already have P(0;20)+P(0;1)+P(0;2) =0.2061 and

$\large \sum_{k=1}^{3}P(20;k)=0.2061+P(20;3)=0.2061+0.205364 \approx 0.4236=42.36\%$

d)

For a binomial distribution the <em>expectance </em>of “succeses” in n trials is np where p is the probability of “succes”, and the expectance of “failures” is nq, so the expectance for withdrawals in 20 students is 20*0.2 = <em>4 withdrawals.</em>

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3 years ago