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2 years ago

What is the ratio of daises to all the flowers in the vase?

Mathematics

1 answer:

ddd [48]2 years ago

3 0

Answer: Do you have the original ration so we can simplify it then??

Step-by-step explanation:

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Leah claims that these figures are not similar. When she compared the heights, she wrote 27. Then she compared the bases and got

Flauer [41]

Answer:

<h2>Leah is actually wrong, because those rectangles are similar.</h2>

Step-by-step explanation:

Remember that similarity is about having proportional sides and congruent angles. When we have congruent sides, then those rectangles are congruent not similar.

In this case, to find the similarity, Leah should compare bases and heights thorugh division, because the ratio between heights and the ratio between bases must be equal. So, let's divide.

$\frac{21}{6}=3.5$

$\frac{7}{2}=3.5$

As you can observe, both ratios are equal.

Therefore, those rectangles are congruent.

4 0

2 years ago

Please help me find the answer ASAP. Thanks

jenyasd209 [6]

This is very easy question write all given and common

3 0

3 years ago

Find x when f(x)=1 . (These means find the input that gives an output of 1.)<br><br> f(x)=1/x-2

Andreyy89

Answer:

x = 1/3

Step-by-step explanation:

1 = 1/x -2

add 2 to both sides

3 = 1/x

x = 1/3

5 0

2 years ago

Solve the system by the<br> substitution method.<br> 7x + y = -6<br> 7x - 3y = 18

Elodia [21]

Answer:

Stdivise 7 aep-by-step explanation:

7 0

3 years ago

Read 2 more answers

Find the limit, if it exists, or type dne if it does not exist.

Phantasy [73]

$\displaystyle\lim_{(x,y)\to(0,0)}\frac{\left(x+23y)^2}{x^2+529y^2}$

Suppose we choose a path along the $x$ -axis, so that $y=0$ :

$\displaystyle\lim_{x\to0}\frac{x^2}{x^2}=\lim_{x\to0}1=1$

On the other hand, let's consider an arbitrary line through the origin, $y=kx$ :

$\displaystyle\lim_{x\to0}\frac{(x+23kx)^2}{x^2+529(kx)^2}=\lim_{x\to0}\frac{(23k+1)^2x^2}{(529k^2+1)x^2}=\lim_{x\to0}\frac{(23k+1)^2}{529k^2+1}=\dfrac{(23k+1)^2}{529k^2+1}$

The value of the limit then depends on $k$ , which means the limit is not the same across all possible paths toward the origin, and so the limit does not exist.

8 0

3 years ago