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elena55 [62]
3 years ago
5

8, 15, 20, 23, 29, 25, 30, 24, 28, 35, 32, 28, 27, 27, 25, 28, 29, 14, 22, 18 what is the outlier?

Mathematics
1 answer:
Dominik [7]3 years ago
5 0

Answer:

17

Step-by-step explanation:

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UNO [17]

Answer:

<em>2 solutions</em>

Step-by-step explanation:

Given the expression

2m/2m+3 - 2m/2m-3 = 1

Find the LCM of the expression at the left hand side:

2m(2m-3)-2m(2m+3)/(2m+3)(2m-3) = 1

open the bracket

4m²-6m-4m²-6m/(4m²-9) = 1

Cross multiply

4m²-6m-4m²-6m = 4m²  - 9

-12m = 4m²  - 9

4m²  - 9+12m = 0

4m² +12m-9 = 0

<em>Since the resulting equation is a quadratic equation, it will have 2 solutions since the degree of the equation is 2</em>

8 0
3 years ago
Look at the picture<br>​
Sonbull [250]

\large\displaystyle\text{$\begin{gathered}\sf 9|x-8| < 36 \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf Divide \ both \ sides \ by \ 9. \end{gathered}$}

  • \large\displaystyle\text{$\begin{gathered}\sf  \frac{9(|x-8|)}{9} < \frac{36}{9}   \end{gathered}$}
  • \large\displaystyle\text{$\begin{gathered}\sf |x-8| < 4 \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf Solve \ Absolute \ Value. \end{gathered}$}

  • \large\displaystyle\text{$\begin{gathered}\sf |x-8| < 4 \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf We \ know \ x-8 < 4 \ and \ x-8 > -4 \end{gathered}$}

<u>                                                                                                                             </u>

         \large\displaystyle\text{$\begin{gathered}\sf x-8 < 4 \ (Condition \ 1) \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf x-8+8 < 4+8 \ (Add \ 8 \ to \ both \ sides) \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf x < 12 \end{gathered}$}

<u>                                                                                                                             </u>

           \large\displaystyle\text{$\begin{gathered}\sf x-8 > -4 \ (Condition \ 2) \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf x-8+8 > -4+8 \ (Add \ 8 \ to \ both \ \ sides) \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf x > 4 \end{gathered}$}

<u>                                                                                                                             </u>

<u />\underline{\boldsymbol{\sf{Answer}}}

\boxed{\large\displaystyle\text{$\begin{gathered}\sf x < 12 \ and \ x > 4 \end{gathered}$} }

\large\displaystyle\text{$\begin{gathered}\sf Therefore,\bf{\underline{the \  correct \ option}} \  \end{gathered}$}\large\displaystyle\text{$\begin{gathered}\sf is \ \bf{\underline{"A"}}. \end{gathered}$}

6 0
2 years ago
Find the percent of 54 to 90
dusya [7]
 54<span> is what </span>percent<span> of </span>90<span> is equal to (</span>54<span> / </span>90<span>) x 100 = 60%. So if you buy an item at </span>$90<span> with </span>$54<span> discounts, you will pay $36 and </span>get<span> 60% discount ...</span>
6 0
3 years ago
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For which positive integer values of $k$ does $kx^2+20x+k=0$ have rational solutions? Express your answers separated by commas a
Musya8 [376]

Answer:

-10,10

Step-by-step explanation:

The given quadratic equation is

k {x}^{2}  + 20x + k = 0

The discriminant of this equation is given by;

D =  {b}^{2}  - 4ac

where a=k, b=20, c=k

For rational solutions, the discriminant must be zero.

{20}^{2}  - 4 \times k \times k = 0

Simplify to get:

400 - 4  {k}^{2}  = 0

This implies that:

400  = 4  {k}^{2}

100 =  {k}^{2}

Take square root to get:

k =   \pm\sqrt{100}

k =  \pm10

k =  - 10 \: or \: k = 10

3 0
3 years ago
Gerald ran 240 yards. Which answer choices are equivalent to the distance he ran?
yulyashka [42]

Answer:

8640 inches

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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