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Readme [11.4K]
3 years ago
8

Simplify the expression (6+I)(9-4i)

Mathematics
1 answer:
Vlada [557]3 years ago
4 0
54 - 24i + 9i + 4
(54 + 4) + (-24i + 9i)
58 - 15i
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Let FS R be a finite set. (a) Prove that F is closed (b) Prove that every point in F is an isolated point.
Lorico [155]

Answer:

a) Suppose that F is ordered in ascending order: F = \{x_1,\ldots, x_n\}. Then, the complement of F can be written as

F^c = (-\infty,x_1)\cup (x_1,x_2)\cup (x_2,x_3)\cup \cdots \cup (x_{n-1}, x_{n})\cup (x_n,+\infty)

which is the union of a finite number of open intervals, then F^c is an open set. Thus, F is a closed subset of the real numbers.

b) Take an arbitrary element of F, let us say x_k. Now, choose a real number \epsilon such that

0 there are not other element of F, because \epsilon is less that the minimum distance between x_k and its neighbors.

In case that k=1 we only consider 0, and if k=n we only consider 0.

Then, all points of F are isolated.

Step-by-step explanation:

8 0
3 years ago
HELP?? A lunch combo has the following options: Entree: Hamburger, Hotdog, Chicken sandwich Side: Apples, Salad Drink: Milk, Wat
murzikaleks [220]

Using the Fundamental Counting Theorem, the sample size of these outcomes is of 12.

<h3>What is the Fundamental Counting Theorem?</h3>

It is a theorem that states that if there are n things, each with n_1, n_2, \cdots, n_n ways to be done, each thing independent of the other, the number of ways they can be done is:

N = n_1 \times n_2 \times \cdots \times n_n

Considering the number of options for Entree, Side and Drink, the parameters are:

n1 = 3, n2 = 2, n3 = 2.

Hence the sample size of outcomes is:

N = 3 x 2 x 2 = 12.

More can be learned about the Fundamental Counting Theorem at brainly.com/question/24314866

#SPJ1

3 0
2 years ago
ASAP ANZWER PleASEEE :)
Hitman42 [59]

Answer:

%80

Step-by-step explanation:

5 0
3 years ago
I need help solving this, it has 2 parts.
Ratling [72]

Answer:

the part of second is 4second p

6 0
3 years ago
HELP!!!
Naddika [18.5K]

Check the picture below, so it reaches the maximum height at the vertex, let's check where that is

h(t)=64t-16t^2+0 \\\\[-0.35em] ~\dotfill\\\\ \textit{vertex of a vertical parabola, using coefficients} \\\\ h(t)=\stackrel{\stackrel{a}{\downarrow }}{-16}t^2\stackrel{\stackrel{b}{\downarrow }}{+64}t\stackrel{\stackrel{c}{\downarrow }}{+0} \qquad \qquad \left(-\cfrac{ b}{2 a}~~~~ ,~~~~ c-\cfrac{ b^2}{4 a}\right) \\\\\\ \left(-\cfrac{ 64}{2(-16)}~~~~ ,~~~~ 0-\cfrac{ (64)^2}{4(-16)}\right)\implies \stackrel{maximum~height}{(2~~,~~\stackrel{\downarrow }{64})}

5 0
2 years ago
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