Answer:
$4.50 per hour
Step-by-step explanation:
Step 1: 27 divided by 6 is 4.50
Step 2: Double check your work by multiplying 4.50 times 6 to make sure you get 27
Given the data below <span>representing the body mass index (bmi) values for 20 females.
17.7 33.5 26.9 22.7 22.2 29.9 23.6 18.3 27.7 23.4 19.2 25.9 22.9 37.7 31.6 28.1 44.9 31.6 25.2 23.9
From the data above, we construct a frequency distribution beginning with a lower class limit of
15.0 and use a class width of 6.0 as follows:
Class iinterval: 15.0 - 21.0 21.0 - 27.0 27.0 - 33.0 33.0 - 39.0 39.0 - 45.0
Frequency: 3 9 5 2 1
From the frequency table, it can be seen that the frequencies started low, increased to a point and then decrease. It can also be seen that the highest frequency of the data is not at the center of the distribution, so the distribution is not symetric.
Therefore, the frequency
distribution does not appear to be roughly a normal distribution, because, "although the frequency start low, increase to some maximum, then decrease, the distribution is not symmetric."</span>
Answer:
(a) 13536.10J
(b) 27072.20J
Step-by-step explanation:
(a) Height of tank (h) = 4 feet = 4/3.2808 = 1.22m
Volume of water in full tank = 4ft×5ft×4ft = 80ft^3
Volume of water in half tank = 1/2 × 80ft^3 = 40ft^3
Density of water = 62.4lb/ft^3
Mass of water = density × volume = 62.4 × 40 = 2496lb = 2496×0.45359kg = 1132.16kg
Work done to empty half of the tank = mgh = 1132.16×9.8×1.22 = 13536.10J
(b) Work done to empty all of the tank = 2 × work done to empty half of the tank= 2 × 13536.10J = 27072.20J
