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What is the volume of a rectangular prism with a base of 24 square feet and a height of 5.25 feet?

Blababa [14]

Rectangular prism is nothing but cuboid.

Volume of a cuboid = length × breadth × height

Base area = length × breadth

It is given that base area = 24 square feet and

height = 5.25 feet

Now, volume = length × breadth × height

= base area × height

= 24 × 5.25

= 126 cubic feet

Hence, the volume of the rectangular prism is 126 cubic feet.

7 0

4 years ago

Please hurry!! Steven and Dan like to play a lot of video games. On Sunday, Dan played 4 fewer than twice the number of hours th

madam [21]

Answer

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Oscar has a piece of pie would that is 9‘ x 9‘ explain how we can divided into two smaller pieces of plywood would the area of t

Dimas [21]

Answer:

1. with the aid of a saw

2.No

Step-by-step explanation:

A. The 9‘ x 9‘ can be divided into two with the aid of a saw .

we have to take into account the area of the shape wic 9'x9'. and then saw the piece at the middle.

b.there are two sides to the second answer

1. the area of the smaller pieces will be smaller than the area of the larger piece

2. when the smaller pieces are placed side by side aain , tere area combined together will be the same as the original piece

5 0

4 years ago

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PLS HELPP its for math

igor_vitrenko [27]

Answer:

y=mx+b man

Step-by-step explanation:

7 0

3 years ago

The probability that a student has a Visa card (event V) is .73. The probability that a student has a MasterCard (event M) is .1

snow_lady [41]

We assumed in this answer that the question b is, Are the events V and M independent?

Answer:

(a). The probability that a student has either a Visa card or a MasterCard is $\\ P(V \cup M) = 0.88$ . (b). The events V and M are not independent.

Step-by-step explanation:

The key factor to solve these questions is to know that:

$\\ P(V \cup M) = P(V) + P(M) - P(V \cap M)$

We already know from the question the following probabilities:

$\\ P(V) = 0.73$

$\\ P(M) = 0.18$

The probability that a student has both cards is 0.03. It means that the events V AND M occur at the same time. So

$\\ P(V \cap M) = 0.03$

The probability that a student has either a Visa card or a MasterCard

We can interpret this probability as $\\ P(V \cup M)$ or the sum of both events; that is, the probability that one event occurs OR the other.

Thus, having all this information, we can conclude that

$\\ P(V \cup M) = P(V) + P(M) - P(V \cap M)$

$\\ P(V \cup M) = 0.73 + 0.18 - 0.03$

$\\ P(V \cup M) = 0.88$

Then, the probability that a student has either a Visa card or a MasterCard is $\\ P(V \cup M) = 0.88$ .

Are the events V and M independent?

A way to solve this question is by using the concept of conditional probabilities.

In Probability, two events are independent when we conclude that

$\\ P(A|B) = P(A)$ [1]

The general formula for a conditional probability or the probability that event A given (or assuming) the event B is as follows:

$\\ P(A|B) = \frac{P(A \cap B)}{P(B)}$

If we use the previous formula to find conditional probabilities of event M given event V or vice-versa, we can conclude that

$\\ P(M|V) = \frac{P(M \cap V)}{P(V)}$

$\\ P(M|V) = \frac{0.03}{0.73}$

$\\ P(M|V) \approx 0.041$

If M were independent from V (according to [1]), we have

$\\ P(M|V) = P(M) = 0.18$

Which is different from we obtained previously;

That is,

$\\ P(M|V) \approx 0.041$

So, the events V and M are not independent.

We can conclude the same if we calculate the probability

$\\ P(V|M)$ , as follows:

$\\ P(V|M) = \frac{P(V \cap M)}{P(M)}$

$\\ P(V|M) = \frac{0.03}{0.18}$

$\\ P(V|M) = 0.1666.....\approx 0.17$

Which is different from

$\\ P(V|M) = P(V) = 0.73$

In the case that both events were independent.

Notice that

$\\ P(V|M)*P(M) = P(M|V)*P(V) = P(V \cap M) = P(M \cap V)$

$\\ \frac{0.03}{0.18}*0.18 = \frac{0.03}{0.73}*0.73 = 0.03 = 0.03$

$\\ 0.03 = 0.03 = 0.03 = 0.03$

3 0

4 years ago