3 years ago

In common core how do you use dominoes

Mathematics

1 answer:

Tems11 [23]3 years ago

7 0

Stack them , one by one .

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An object is launched at 28 meters per second (m/s) from a 336-meter tall platform. The equation for the object's height s at ti

kondaur [170]

Answer:343 m

Step-by-step explanation:

Given

launch velocity of object is $u=28\ m/s$

height of Platform $h=336\ m$

height of object is given by

$s(t)=-7t^2+14t+336$

For maximum height velocity of object is zero

i.e. $\frac{ds}{dt}=0$

$\frac{ds}{dt}=-14t+14+0=0$

$t=\frac{14}{14}=1\ s$

Therefore after 1 sec object achieves maximum height

$s(1)=-7(1)+14(1)+336$

$s(1)=343\ m$

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4 years ago

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