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alexdok [17]
3 years ago
10

Which expression means the same as 3 x 3/4?

Mathematics
1 answer:
Svetllana [295]3 years ago
4 0
Answer: 3x3/4=(3x3)/(1x4)

Explain: Because if you break up the expression, 3/4=3 divided by 4, then the expression will become 3x3 divided by 4( or 3x3/4)

3x3/4=9/4=2.25

•(3x3)/(1x4)=9/4=2.25
•(3x1)/(3x4)=3/12=0.25
•(3/1)x(4/3)=3x1.333=3.999
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3 years ago
Suppose that a company needs 1, 200,000 items during a year and that preparation for each production run costs $500. Suppose als
MAVERICK [17]

Answer:

The number of items in each production run so that the total costs of production and storage are minimized is 8165 items/run

Step-by-step explanation:

We will use the following variables:

Q = Quantity being ordered

Q* = the optimal order Quantity: the result being sought

D = annual Demand for the item, over the year

P = unit Production cost

S = cost of setting up a production run, regardless of the number of units in the production run (fixed cost per production run)

H = annual cost to Hold one unit

It is important to note which variables are annualized, which are per-order and which are per-unit.

Using the variables, here are the components of the first equation

Total Cost, TC = PC + SC + HC

PC = P x D :  Production Cost = unit Production cost times the annual Demand

SC = (D x S)/Q : Setting up Cost = annual Demand times cost per production setup, divided by the order Quantity (number of units)

HC = (H x Q)/2: Holding Cost = annual unit Holding cost times order Quantity (number of units), divided by 2 (because throughout the year, on average the warehouse is half full).

So TC = PC + SC + HC =  (P x D) + ((D x S)/Q) + ((H x Q)/2) = PD + (DS/Q) + HQ/2

To obtain the optimal order quantity, Q* that minimizes TC, at the minimum TC, dTC/dQ = 0

dTC/dQ = (H/2) – (D x S)/(Q²) = 0

(H/2) – (D x S)/(Q²) = 0

Solving for Q, which is Q* at this point.

(Q*)² = 2DS/H

Q* = √(2DS/H)

D = annual demand for the item = 200000

S = cost of setting up a production run, regardless of the number of units in the production run (fixed cost per production run) = $500

H = annual cost to Hold one unit = $3

Q* = √(2×200000×500/3) = 8164.97 = 8165 items.

3 0
3 years ago
encuentra el termino indicado de cada sucesion aritmetica #12avo termino de 2,4,6. #10mo termino de 1,-1-5. #8vo termino de -1,1
Maslowich

Step-by-step explanation:

hope it will helps you my answer

4 0
3 years ago
What's the unit rate for 2,500 kilobytes in 5 minutes
Aleks [24]
The ratio is 500:1 if you are looking for that
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4 0
3 years ago
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Westkost [7]

Answer:

r=20÷7

Step-by-step explanation:

7r=4•5

r=20÷7

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