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nikklg [1K]
3 years ago
5

Please can someone help me answer the question in the picture

Mathematics
1 answer:
Firdavs [7]3 years ago
7 0
(X+3)(x+7) X+7
————— = ——
(X-3)(x+3) X-3
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Given f(x) and g(x) = f(k⋅x), use the graph to determine the value of k<br>2<br>-2<br>1/2<br>-1/2
Umnica [9.8K]

Answer:

Step-by-step explanation:

Using the graph we can notice something

let's take the abscissa  -2 and -4

  • the ordinate that goes with -2 using g is 0
  • the ordinate that goes with  -4 using f is 0

so we can say that :

f(-4)=g(-2)

wait we khow that g(x)=f(k*x)

so x= -2 then let's replace it in the expression : f(k*x)

we get f(-4)=g(-2)=f[k*(-2)]

let's solve the equation: -2k = -4

                                               k = -4/-2

                                                k=2

so finally we get k=2

let's check :

from the graph we get :

  • f(-2)=2
  • g(-1)=2

we have (-1)*2 = -2

so it is true

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3 years ago
In circle o, which term does not describe PR
LuckyWell [14K]
The answer is C Radius because look o. the outside it's clearly bigger
8 0
4 years ago
I need help with my homework pls gotta one hour to turn in ​
Helga [31]

Answer:

12 brown

Step-by-step explanation:

4 0
3 years ago
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An ice cream store sells 3drinks, in 4sizes, and 8 flavors. In how many ways can a customer order a drink?
Sedbober [7]
You would take 3 x 4 which equals 12. And then you would take 12 x8 which would equal 96
7 0
4 years ago
Find the vertex and length of the latus rectum for the parabola. y=1/6(x-8)^2+6
Ivan

Step-by-step explanation:

If the parabola has the form

y = a(x - h)^2 + k (vertex form)

then its vertex is located at the point (h, k). Therefore, the vertex of the parabola

y = \dfrac{1}{6}(x - 8)^2 + 6

is located at the point (8, 6).

To find the length of the parabola's latus rectum, we need to find its focal length <em>f</em>. Luckily, since our equation is in vertex form, we can easily find from the focus (or focal point) coordinate, which is

\text{focus} = (h, k +\frac{1}{4a})

where \frac{1}{4a} is called the focal length or distance of the focus from the vertex. So from our equation, we can see that the focal length <em>f</em> is

f = \dfrac{1}{4(\frac{1}{6})} = \dfrac{3}{2}

By definition, the length of the latus rectum is four times the focal length so therefore, its value is

\text{latus rectum} = 4\left(\dfrac{3}{2}\right) = 6

5 0
3 years ago
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