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Evgesh-ka [11]
3 years ago
7

Engineers want to design seats in commercial aircraft so that they are wide enough to fit 99​% of all males.​ (accommodating 100

% of males would require very wide seats that would be much too​ expensive.) men have hip breadths that are normally distributed with a mean of 14.6 in. and a standard deviation of 0.8 in. find upper p 99. that​ is, find the hip breadth for men that separates the smallest 99​% from the largest 1​%.
Mathematics
1 answer:
Helga [31]3 years ago
7 0
Hip Breadths and Aircraft Seats
Engineers want to design seats in commercial aircraft so that they are wide enough to fit 98% of all males. (Accommodating 100% of males would be too expensive.) Men have hip breadths that are normally distributed with a mean of 14.4 in. and a standard deviation of 1.0 in. Find P 98. That is, find the hip breadth for men that separates the smallest 98% from the largest 2%.
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Answer:

-8x

Step-by-step explanation:

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1 year ago
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The Candela brothers own two pizza restaurants, one on Park Street and one on Bridge Road.
koban [17]

The mean, median and mode are measures of central tendency, that is they tend to indicate the location middle of the data

Required values;

(a) The performance for the week for Park Street

  • Revenue is <u>Q₂ < $7,500 < Q₃</u>
  • The sales for the week is better than <u>72.91%</u> of all sales

The performance for the week for Bridge Road

  • Revenue; <u>Q₂ < $7,100 < Q₃</u>
  • The sale for the week is better than <u>59.87%</u> of all sales

(b) The mean is <u>$3611</u>

The median is $<u>3,600</u>

The standard deviation is $<u>3250</u>

The Interquartile range is $<u>6075</u>

Reason:

The table of values that maybe used to find a solution to the question is given as follows;

\begin{array}{|l|l|l|}\mathbf{Variable} &\mathbf{Park}&\mathbf{Bridge}\\N&36&40\\Mean&6611&5989\\SE \ Mean&597&299\\StDev&3580&1794\\Minimum&800&1800\\Q_1&3600&5225\\Median&6600&6000\\Q_3&9675&7625\\Maximum&14100&8600\end{array}\right]

(a) Park Street revenue = $7,500

Bridge Road's revenue = $7,100

The two stores sold close to but below the 75th percentile

Bridge Road revenue;

The z-score is given as follows;

Z = \dfrac{x - \mu }{\sigma }

  • Z = \dfrac{7100 - 5,989 }{1794 } \approx 0.6193

From the Z-Table, we have;

The percentile= 0.7291

  • Therefore, the sale for the week for Park Street is better than <u>72.91%</u> of all the sales

Park Street revenue;

The z-score is given as follows;

  • Z = \dfrac{7500 - 6611}{3580} \approx 0.25

From the Z-Table, we have;

The percentile = <u>0.5987</u>

  • Therefore, the sale for the week is better than <u>59.87 %</u> of all the sales

(b) Given that the operating cost is $3,000, frim which we have;

The subtracted value is subtracted from the mean and median to find the new value

Profit = The revenue - Cost

New mean = 6611 - 3000 = 3611

  • The new mean = <u>$3,611</u>

The new median = 6600 - 3000 = 3600

  • The new median = <u>$3,600</u>

The standard deviation and the interquartile range remain the same, therefore, we have;

  • The standard deviation = <u>$3,580</u>

The interquartile range = 9675 - 3600 = 6075

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Learn more here:

brainly.com/question/21133077

brainly.com/question/23305909

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1 year ago
What are the domain and range of the function x^2-2x^2-4?
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The Quadratic Function has the domain as the set of all real numbers.

For the range, start from minimum value to maximum value.

But because the parabola is downward as a < 0. Thus, there are no minimum value but the maximum value instead.

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Lelu [443]
The mean is the average of a set of numbers.

So if the remaining 40% of students score 100 points, and the 60% score like 50 points, then the mean would still be 70 points because of the 40% of students that scored super high.

So yes, it can be true.
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Learning of Galileo’s imprisonment. You can also look this up on Brainly and Google
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