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Evgesh-ka [11]
3 years ago
7

Engineers want to design seats in commercial aircraft so that they are wide enough to fit 99​% of all males.​ (accommodating 100

% of males would require very wide seats that would be much too​ expensive.) men have hip breadths that are normally distributed with a mean of 14.6 in. and a standard deviation of 0.8 in. find upper p 99. that​ is, find the hip breadth for men that separates the smallest 99​% from the largest 1​%.
Mathematics
1 answer:
Helga [31]3 years ago
7 0
Hip Breadths and Aircraft Seats
Engineers want to design seats in commercial aircraft so that they are wide enough to fit 98% of all males. (Accommodating 100% of males would be too expensive.) Men have hip breadths that are normally distributed with a mean of 14.4 in. and a standard deviation of 1.0 in. Find P 98. That is, find the hip breadth for men that separates the smallest 98% from the largest 2%.
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Can you explain how you got the answer as well please?
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Answer:

A. 35

Step-by-step explanation:

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5 0
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Suppose we have a binomial experiment in which success is defined to be a particular quality or attribute that interests us.
mestny [16]

For a binomial experiment in which success is defined to be a particular quality or attribute that interests us, with n=36 and p as 0.23,  we can approximate p hat by a normal distribution.

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n*q = 36*0.77=27.22>5

and therefore, p hat can be approximated by a normal random variable, because n*p>5 and n*q>5.

The question is incomplete, a possible complete question is:

Suppose we have a binomial experiment in which success is defined to be a particular quality or attribute that interests us.

Suppose n = 36 and p = 0.23. Can we approximate p hat by a normal distribution? Why? (Use 2 decimal places.)

n*p = ?

n*q = ?

Learn to know more about binomial experiments at

brainly.com/question/1580153

#SPJ4

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