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3 years ago

13

Jo is looking for a new part-time job as a plumber. She responds to a classified ad for a position that pays 44.9K. What would h

er weekly salary be to the nearest cent if she gets this job?

1 answer:

hoa [83]3 years ago

3 0

Answer:

855.77

Step-by-step explanation:

44500/52 equals 855.77

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Brewed decaffeinated coffee contains some caffeine. We want to estimate the amount of caffeine in 8 ounce cups of decaf coffee a

rusak2 [61]

Answer:

We would have to take a sample of 62 to achieve this result.

Step-by-step explanation:

Confidence level of 95%.

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.025 = 0.975$ , so Z = 1.96.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

Assume that the standard deviation in the amount of caffeine in 8 ounces of decaf coffee is known to be 2 mg.

This means that $\sigma = 2$

If we wanted to estimate the true mean amount of caffeine in 8 ounce cups of decaf coffee to within /- 0.5 mg, how large a sample would we have to take to achieve this result?

We would need a sample of n.

n is found when $M = 0.5$ . So

$M = z\frac{\sigma}{\sqrt{n}}$

$0.5 = 1.96\frac{2}{\sqrt{n}}$

$0.5\sqrt{n} = 2*1.96$

Dividing both sides by 0.5

$\sqrt{n} = 4*1.96$

$(\sqrt{n})^2 = (4*1.96)^2$

$n = 61.5$

Rounding up

We would have to take a sample of 62 to achieve this result.

8 0

3 years ago

Which is the correct interpretation of the x-intercepts of the function? Their difference is the number of the most promo codes

GrogVix [38]

Answer:

d

Step-by-step explanation:

4 0

3 years ago

Uh, I need help with this question (10 points)

Igoryamba

Answer:

2 cups

Step-by-step explanation:

8 0

2 years ago

The density of people (number of people per mile) during the evening rush hour for the 5 mile stretch along a certain sidewalk i

Kisachek [45]

Answer:

a. $\int\limits^5_0 {f(x)} \, dx$

Step-by-step explanation:

Since f(x) is the function for the populational density at a certain sidewalk for a 5 mile stretch, a definite integral of that function will yield the total number of people within the integration intervals. If we are interested in the number of people in the whole 5 mile stretch, we must integrate f(x) from x = 0 miles to x = 5 miles:

$\int\limits^5_0 {f(x)} \, dx$

Therefore, the answer is alternative a.

5 0

3 years ago

Find the greatest common factor of these two expressions 18y^6w^2 and 27y^5 w^4 u^7

drek231 [11]

Answer:

9 $y^{5}$ $w^{2}$

Step-by-step explanation:

Find what both expressions have in common

3 0

2 years ago