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3 years ago

10

25 POINTS SOMEONE HELP ME OUT WITH THIS PLEASEEEE BRAINLIEST ANSWER

1 answer:

zloy xaker [14]3 years ago

3 0

1. $y=7x-1$

2. $y=3x+b$
<u> </u><u>Sub (1, -5) into equation to find '</u><em><u>b'</u></em><u />
$-5=3(1)+b$
$-8=b$

$y=3x-8$

3. $x=-7$

4. $y=4$

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$$\frac{5 !}{4 !(5-4) !}(2 x)^{1} y^{4}= 10 x y^{4}$

$$\frac{5 !}{5 !(5-5) !}(2 x)^{0} y^{5}=y^{5}$

Substitute these into the above expansion.

$(2x+y)^5=32 x^{5}+80 x^{4} y+80 x^{3} y^{2}+40 x^{2} y^{3}+10 x y^{4}+y^{5}$

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