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3 years ago

78000 rounded to the nearest ten thousand

Mathematics

1 answer:

GenaCL600 [577]3 years ago

8 0

78,000 rounded to the nearest ten thousand is 80,000.

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Answer:

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Step-by-step explanation:

we know that

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have the coordinates

D(8,-6) E(-1,-3) F(-2,5)

step 1

Find the length side DE

D(8,-6) E(-1,-3)

substitute in the formula

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$d=\sqrt{(3)^{2}+(9)^{2}}$

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step 2

Find the length side EF

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substitute in the formula

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step 3

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step 4

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$d_E_F=\sqrt{65}\ units$

$d_D_F=\sqrt{221}\ units$

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