78000 rounded to the nearest ten thousand

What is 2-1 reversed? A.1 B.-1 C.2 D. -2

vovikov84 [41]

2-1 reversed is turning it around : 1-2 which equals -1 because there is one left over. B is your answer and hoped I helped!

5 0

3 years ago

Read 2 more answers

( HELP ASAP! EASY POINTS ) The picture below shows a box sliding down a ramp:

TEA [102]

Answer:

AC = 14 cosec(68)

Explanation:

Here given:

angle: 68°

opposite: 14 ft

hypotenuse: AC

Use sine rule:

$\rightarrow \sf sin(x) = \dfrac{opposite}{hypotenuse}$

$\rightarrow \sf sin(68) = \dfrac{14}{AC}$

$\rightarrow \sf AC= \dfrac{14}{ sin(68) }$

$\rightarrow \sf AC= 14 \ cosec(68)$

4 0

1 year ago

Use the figure.<br> What is the measure of angle 2?

zhuklara [117]

Answer:

3x+9

Step-by-step explanation:

i think since it is across from there

3 0

3 years ago

Read 2 more answers

Assume that a company hires employees on Mondays, Tuesdays, or Wednesdays with equal likelihood.a. If two different employees ar

horsena [70]

Answer:

$P(A) = \frac{1}{9}$

$P(B) = \frac{1}{3}$

$P(C) = \frac{1}{729}$

Step-by-step explanation:

We know that:

Only employees are hired during the first 3 days of the week with equal probability.

2 employees are selected at random.

So:

A. The probability that an employee has been hired on a Monday is:

$P(M) = \frac{1}{3}$ .

If we call P(A) the probability that 2 employees have been hired on a Monday, then:

$P(A) =P(M\ and\ M)\\\\P(A)=( \frac{1}{3})(\frac{1}{3})\\\\P(A) = \frac{1}{9}$

B. We now look for the probability that two selected employees have been hired on the same day of the week.

The probability that both are hired on a Monday, for example, we know is $P(A) = \frac{1}{9}$ . We also know that the probability of being hired on a Monday is equal to the probability of being hired on a Tuesday or on a Wednesday. But if both were hired on the same day, then it could be a Monday, a Tuesday or a Wednesday.

So

$P(B) = \frac{1}{9} + \frac{1}{9} + \frac{1}{9}\\\\P(B) = \frac{1}{3}$ .

C. If the probability that two people have been hired on a specific day of the week is $3(\frac{1}{3}) ^ 2$ , then the probability that 7 people have been hired on the same day is: