What is the center of the circle x² + y2 - 16 = 0?
1 answer:
You might be interested in
Answer:
Rhombus Side = sqr root [(34 / 2)^2 + (30 / 2)^2]
Rhombus Side = sqr root [17^2 + 15^2]
Rhombus Side = sqr root [289 + 225}
Rhombus Side = sqr root [514]
Rhombus Side = 22.6715680975
Rhombus Perimeter = side * 4 = 90.68627239 cm
Step-by-step explanation:
