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Annette [7]
3 years ago
13

what is the maximum volume of water a hamster bath could hold with a depth of 1 2/3 inches, a length of 2 1/3 inches, and width

of 2 inches?
Mathematics
2 answers:
adoni [48]3 years ago
8 0
1 2/3 = 5/3


2 1/3 = 7/3


2 = 2


5/3 * 7/3 * 2 = 70/9 cubic inches = 0.127455 liters
Gennadij [26K]3 years ago
8 0

7 7/9 inches squared

You might be interested in
Let f( x)= sin(x) Let g(x)=cos(x) a) Sketch the graph of f^2 b) Sketch the graph of g^2 c) Sketch the graph of f^2+g^2
ZanzabumX [31]
Given:
f(x) = sin(x)
g(x) = cos(x).

Note that because sin²x + cos²x = 1, the value for f²+g² should be equal to 1.
Create the table shown below.

       x           f²          g²        f² + g²
--------  ---------- -----------   ------------
-π                0             1               1
-0.8π  0.3455  0.6545              1
-0.6π  0.9045  0.0955              1
-0.4π  0.9045  0.0955              1
-0.2π  0.3455  0.6545              1
      0            0             1              1
 0.2π  0.3455  0.6545              1
 0.4π  0.9045  0.0955             1
 0.6π  0.9045  0.0955             1
0.8π   0.3455  0.6545             1
     π             0            1              1

A sketch is shown in the figure below.



5 0
3 years ago
I just need the bonus points for other assignment, it's easy.
Tema [17]

Answer:

159/day

Step-by-step explanation:

6 0
3 years ago
This cuboid is made from cm squares
11Alexandr11 [23.1K]

Answer:

Step-by-step explanation:

Each signal unit cubes are 1 cm to each side

the dimensions of the large cube is 4 by 6 by 3      width height and depth

a) volume of the cube   Vol = area of the base times height  

              area of the base = the width times the depth  

              Volume = Base Depth

                            =  Width x Depth x Height

                            =      4 x 3 x 6

                            =       12 x 6

                Vol      =   72 cm ³

b )  the volume of the smaller cuboid has different dimensions    

             the smaller cube is 2 by 2 by 1      width height and depth

          Volume = Base Depth

                            =  Width x Depth x Heigh

                            =    2 x 2 x 1  

 Vol smaller cuboid    =   4

      How many smaller cubes can be made?

            The obvious answer might be to straight up divide the large cube volume by the smaler cuboid volume. That might work IF all of the cuboid dimensions divide evenly into the cube dimensions.

  Number of cuboid  =   Volume of the cube  /  Volume of the cuboid

                                  =             72 / 4

                                  =        18

Check this answer by dividing the dimension of the cube by the cuboid

         4 by 6 by 3

         2 by 2 by 1

      (4/2) by (6/2) by (3/1)

        2    by    3   by     3       = 2 x 3 x 3     =    18

3 0
3 years ago
Find all solutions in the interval [0, 2π). <br> 2 sin2x = sin x
tester [92]

Answer:

The solutions on the given interval are :

0

\pi

\cos^{-1}(\frac{1}{4})

-\cos^{-1}(\frac{1}{4})+2\pi

Step-by-step explanation:

We will need the double angle identity \sin(2x)=2\sin(x)\cos(x).

Let's begin:

2\sin(2x)=\sin(x)

Use double angle identity mentioned on left hand side:

2\cdot 2\sin(x)\cos(x)=\sin(x)

Simplify a little bit on left side:

4\sin(x)\cos(x)=\sin(x)

Subtract \sin(x) on both sides:

4\sin(x)\cos(x)-\sin(x)=0

Factor left hand side:

\sin(x)[4\cos(x)-1]=0

Set both factors equal to 0 because at least of them has to be 0 in order for the equation to be true:

\sin(x)=0 \text{ or } 4\cos(x)-1=0

The first is easy what angles \theta are y-coordinates on the unit circle 0. That happens at 0 and \pi on the given range of x (this x is not be confused with the x-coordinate).

Now let's look at the second equation:

4\cos(x)-1=0

Isolate \cos(x).

Add 1 on both sides:

4 \cos(x)=1

Divide both sides by 4:

\cos(x)=\frac{1}{4}

This is not as easy as finding on the unit circle.

We know \arccos( ) will render us a value between 0 and 2\pi.

So one solution on the given interval for x is x=\cos^{-1}(\frac{1}{4}).

We know cosine function is even.

So an equivalent equation is:

\cos(-x)=\frac{1}{4}

Apply \cos^{-1} to both sides:

-x=\cos^{-1}(\frac{1}{4})

Multiply both sides by -1:

x=-\cos^{-1}(\frac{1}{4})

This going to be negative in the 4th quadrant but if we wrap around the unit circle, 2\pi , we will get an answer between 0 and 2\pi.

So the solutions on the given interval are :

0

\pi

\cos^{-1}(\frac{1}{4})

-\cos^{-1}(\frac{1}{4})+2\pi

5 0
3 years ago
Sophia has $8 to spend on lunch. Does she have enough money for a sandwich, a drink, and a bag of chips?
timofeeve [1]

Answer:

AYYYYY IREADY! memoriesヾ(≧▽≦*)o

ALright the answer is yes, and she will have $1 left.

4 0
3 years ago
Read 2 more answers
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