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jeka94
3 years ago
7

Hi, can somoene please check why my solution and explain why I get the wrong answer.

Mathematics
1 answer:
trapecia [35]3 years ago
4 0

Answer:

a_n=(1-n)2^n+3^n

Step-by-step explanation:

You are correct down to the part where you add the partial results:

a_n=a_n^h+a_n^p=A3^n+B2^n-n2^n\\\text{Using the given starter values, we can find A, B:}\\a_0=2=A\\a_1=7=3A+2B+2\\\text{has solution A=1, B=1, so ...}\\\\a_n=3^n+2^n-n2^n

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