K=7
Hope this helps!! Can I please have brainliest?
Answer:
The required answer is
.
Step-by-step explanation:
Consider the provided numbers:
We need to subtract in base 4.

The place value of 201 is:
1 is at units place, 0 is at four's place and 2 is at 4 squared place.
The place value of 32 is:
2 is at units place and 3 is at four's place.
201
- 32
Start subtracting the numbers from the unit place.
Here, we need to subtract 2 from 1, which is not possible so borrow 4 from the four's place but there is 0 at four's place so borrow from 4 squared place and change 2 to 1.
Also change 0 to 4 because we have borrow 4 from squared place.
Now 1 can borrow 4 from the four's place which will become 1+4=5 and change 4 at four's place to 3.
Now the number will look like this:
135
- 32
Now subtract the number as shown.
135
<u>- 32</u>
103
Hence, the required answer is
.
Answer:
Perron–Frobenius theorem for irreducible matrices. Let A be an irreducible non-negative n × n matrix with period h and spectral radius ρ(A) = r. Then the following statements hold. The number r is a positive real number and it is an eigenvalue of the matrix A, called the Perron–Frobenius eigenvalue.
Solution:
<u>Note that:</u>
- Given angles: w + 8° and 48°
- w + 8 + 48 = 180
<u>Solve for w in the equation "w + 8 + 48 = 180".</u>
- => w + 8 + 48 = 180
- => 56 + w = 180
- => w = 180 - 56
- => w = 124°
The value of w is 124.