For each pair of shapes decide whether they are congruent similar or neither

kiruha [24]

Answer:

1.1

Step-by-step explanation:

Write out a long division problem! Since you can't have a decimal in the divisor, multiply both numbers by 10. This will leave you with 39.6÷36. Now all you have to do is follow the steps and end up with an answer of 1.1

6 0

1 year ago

Can someone help me with this please?

MrRa [10]

Die haben sich schon in der Schule gesehen und 5 bis drei z die Frau A bist du noch mal in der Nähe

4 0

2 years ago

44. Express each of these system specifications using predicates, quantifiers, and logical connectives. a) Every user has access

DENIUS [597]

Answer:

a. ∀x (User(x) → (∃y (Mailbox(y) ∧ Access(x, y))))

b. FileSystemLocked → ∀x Access(x, SystemMailbox)

c. ∀x ∀y ((Firewall(x) ∧ Diagnostic(x)) → (ProxyServer(y) → Diagnostic(y))

d. ∀x (ThroughputNormal ∧(ProxyServer(x)∧ ¬Diagnostic(x))) → (∃y Router(y)∧Functioning(y))

Step-by-step explanation:

a)

Let the domain be users and mailboxes. Let User(x) be “x is a user”, let Mailbox(y) be “y is a mailbox”, and let Access(x, y) be “x has access to y”.

∀x (User(x) → (∃y (Mailbox(y) ∧ Access(x, y))))

(b)

Let the domain be people in the group. Let Access(x, y) be “x has access to y”. Let FileSystemLocked be the proposition “the file system is locked.” Let System Mailbox be the constant that is the system mailbox.

FileSystemLocked → ∀x Access(x, SystemMailbox)

(c)

Let the domain be all applications. Let Firewall(x) be “x is the firewall”, and let ProxyServer(x) be “x is the proxy server.” Let Diagnostic(x) be “x is in a diagnostic state”.

∀x ∀y ((Firewall(x) ∧ Diagnostic(x)) → (ProxyServer(y) → Diagnostic(y))

(d)

Let the domain be all applications and routers. Let Router(x) be “x is a router”, and let ProxyServer(x) be “x is the proxy server.” Let Diagnostic(x) be “x is in a diagnostic state”. Let ThroughputNormal be “the throughput is between 100kbps and 500 kbps”. Let Functioning(y) be “y is functioning normally”.

∀x (ThroughputNormal ∧(ProxyServer(x)∧ ¬Diagnostic(x))) → (∃y Router(y)∧Functioning(y))

4 0

3 years ago

<1 is a complement of <2, and m<1=66. find <2

Furkat [3]

Answer:

114

Step-by-step explanation:

that's supplementary

6 0

3 years ago

A car traveled from Los Angeles to San Francisco in 6 hours at an average rate of x miles per hour. If the car returned along th

Alenkinab [10]

Answer:

A

Step-by-step explanation:

What we need to know simply is the time taken for both trips. We know the car spent 6 hours on the first leg, that is settled.

What we do not know is the time spent on the second leg. To get the time spent on the second leg of the journey, we only need to get the total distance divided by the speed.

We can get the distance using the first part of the question. The time is 6 hours and the speed is x miles per hour, the total distance is this 6x miles.

Now we need to know the time spent on the second leg of the journey. We know that the distance is the same. Hence the time spent is 6x/y where y is the speed for the second leg and 6x is the length of each leg

Now the total time spent is thus (6x/y +6) hours. We need to however convert this to minutes. We do this by multiplying by 60

(6x/y + 6) * 60

4 0

3 years ago