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yaroslaw [1]
3 years ago
15

What is the lower bound of 8000? someone help me pleaseeee

Mathematics
2 answers:
suter [353]3 years ago
8 0

Answer:

7500

Step-by-step explanation:

Stells [14]3 years ago
5 0
The man rushes through your door with his fists in the air, all of the sudden your vision went black, and he had stolen your points.
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A house costs $600 more than twelve times the lot on which it was built. If the lot cost x dollars, what did the house cost? Whi
Mnenie [13.5K]
House=600+12lot
lot=x
house=600+12x

answer is first expresion
7 0
2 years ago
Read 2 more answers
The shortest side of an isosceles triangle is 2x - 3 inches long. the longer sides are 6 inches longer than the shortest side. t
Zolol [24]
Side 1 = short side = 2x-3
side 2 = longer side = (short side) + 6 = (2x-3)+6 = 2x+3
side 3 = side 2 = 2x+3

Side 2 and side 3 are the longer two congruent sides

Add up the three sides and set them equal to the given perimeter of 33. Solve for x

(side1)+(side2)+(side3) = perimeter
(2x-3)+(2x+3)+(2x+3) = 33
(2x+2x+2x) + (-3+3+3) = 33
6x+3 = 33
6x+3-3 = 33-3
6x = 30
6x/6 = 30/6
x = 5

If x = 5, then the longer sides are 2*x+3 = 2*5+3 = 10+3 = 13 inches each
(note: the short side is 2*x-3=2*5-3=10-3 = 7 inches)

Answer: 13 inches
8 0
3 years ago
The cost of hiring a surfboard involves an up-front fee plus an hourly rate. Three hours of hire costs $50 and 7 hours costs $90
siniylev [52]

Answer:

...... . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

6 0
3 years ago
At 95% confidence, how large a sample should be taken to obtain a margin of error of 0.03 for the estimation of a population pro
Gnom [1K]

Answer:

A sample of 1068 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

At 95% confidence, how large a sample should be taken to obtain a margin of error of 0.03 for the estimation of a population proportion?

We need a sample of n.

n is found when M = 0.03.

We have no prior estimate of \pi, so we use the worst case scenario, which is \pi = 0.5

Then

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.96\sqrt{\frac{0.5*0.5}{n}}

0.03\sqrt{n} = 1.96*0.5

\sqrt{n} = \frac{1.96*0.5}{0.03}

(\sqrt{n})^{2} = (\frac{1.96*0.5}{0.03})^{2}

n = 1067.11

Rounding up

A sample of 1068 is needed.

8 0
2 years ago
Is -6.743743… a rational or irrational number?
yaroslaw [1]

It's rational because it contains a repeating digit pattern, 743 (first option).

In particular, if

<em>x</em> = -6.743743…,

then

1000<em>x</em> = -6,743.743743… .

Subtracting, we can eliminate the trailing end and solve for <em>x</em> exactly:

1000<em>x</em> - <em>x</em> = -6,743.743743… - (-6.743743…)

999<em>x</em> = -6,737

<em>x</em> = -6,737/999

8 0
3 years ago
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