Answer:
We have
k^2 - 25f^2 + 5kf - 25f^2 =
k^2 - (5f)^2 + 5f( k - 5f) =
( k - 5f )( k + 5f ) + 5f( k - 5f ) =
( k - 5f )( k + 5f + 5f ) =
( k - 5f )( k + 10f );
Step-by-step explanation:
1. B she started with 36 photographs,
22 = b - 18 + 13 - 9
b = 22 + 18 - 13 + 9
b = 36
I translated it into an equation, so I would say C, but since B is the only one with the right answer...
2. A
78 - 5 = 73
73 × 365 = 26645
3. D
4. D
5. A
40 × 86 = 3440
Answer:
The score of 271.2 on a test for which xbar = 240 and s = 24 has a higher relative position than a score of 63.6 on a test for which xbar = 60 and s = 6.
Step-by-step explanation:
Standardized score, z = (x - xbar)/s
xbar = mean, s = standard deviation.
For the first test, x = 271.2, xbar = 240, s = 24
z = (271.2 - 240)/24 = 1.3
For the second test, x = 63.6, xbar = 60, s = 6
z = (63.6 - 60)/6 = 0.6
The standardized score for the first test is more than double of the second test, hence, the score from the first test has the higher relative position.
Hope this Helps!!!
Answer:
something perpendicular probably
11 meteres per second could’ve the fastest he could travel
