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Mashutka [201]
3 years ago
11

Factor the expression. k2 + 5kf – 50f2

Mathematics
2 answers:
g100num [7]3 years ago
4 0

Answer:

We have

k^2 - 25f^2 + 5kf - 25f^2 =

k^2 - (5f)^2 + 5f( k - 5f) =

( k - 5f )( k + 5f ) + 5f( k - 5f ) =

( k - 5f )( k + 5f + 5f ) =

( k - 5f )( k + 10f );

Step-by-step explanation:


Sunny_sXe [5.5K]3 years ago
4 0

Answer:  The required factored form of the given expression is (k-5f)(k+10f).

Step-by-step explanation:  We are given to factor the following quadratic expression :

E=k^2+5kf-50f^2~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

To factor the given expression, we need two integers with sum 5 and product -50 and those two integers are 10 and -5.

The factorization of expression (i) is as follows :

E\\\\=k^2+5kf-50f^2\\\\=k^2+10kf-5kf-50f^2\\\\=k(k+10f)-5f(k+10f)\\\\=(k-5f)(k+10f).

Thus, the required factored form of the given expression is (k-5f)(k+10f).

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Step-by-step explanation:

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NISA [10]

Answer:   \bold{b)\quad \dfrac{2\pi}{3},\dfrac{4\pi}{3},0}

<u>Step-by-step explanation:</u>

Note the following identities: tan² x = sec²x - 1

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-(-2)^4 = 16

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