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cupoosta [38]
3 years ago
15

What is described as a line, segment or Ray that bisects a segment at a right angle?

Mathematics
2 answers:
Elena L [17]3 years ago
7 0

Answer:

something perpendicular probably

Andrej [43]3 years ago
6 0

Answer:

perpendicular bisector

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8 meters increased by 25% is
Kobotan [32]
10 meters, because 25 percent of 8 is 2, 2 plus 8 is 10.
5 0
4 years ago
Read 2 more answers
The distance traveled by a falling object is modeled by the equation below, where s is the distance fallen, g is gravity, and t
iren [92.7K]

Answer:

meters per seconds squared

Step-by-step explanation:

seconds squared cancel out and you're leftvwith just meters when

meters/seconds squared is multiplied with the seconds squared in t^2

g means gravity and

gravity is 9.8 meters per second squared

nasa

4 0
2 years ago
A rose garden is formed by joining a rectangle and a semicircle, as shown below. The rectangle is 31 ft long and 20 ft wide. If
forsale [732]
<h3>Answer:</h3>

133 ft

<h3>Step-by-step explanation:</h3>

Given in the question,

length of the rectangle = 31 ft

width of the rectangle= 20 ft

diameter of semicircle = 20 ft

radius of semicircle = 20/2 ft = 10 ft

<h3>Formula to use:</h3>

perimeter of rectangle + perimeter of semicircle

perimeter of rectangle = 2(l+w)

perimeter of semicircle = 1/2(2πr)

<h3>Plug values in the formula above</h3>

2(31 + 20) + 3.14(10)

133.4 ft

≈ 133 ft

8 0
3 years ago
What is the midpoint of the line segment with endpoints(-2,-2) and (4,6)
Ann [662]

Answer:

The midpoint of points (-2,-2)\ and\ (4,6) is (1,2).

Step-by-step explanation:

Given points are (-2,-2)\ and\ (4,6). We need to find the midpoint of the line segment.

The formula of finding midpoints between the point (x_1,y_1)\ and\ (x_2,y_2) is

(\frac{x_1+x_2}{2}),(\frac{y_1+y_2}{2})\ Equation(1)

W have points (x_1,y_1)=(-2,-2). And (x_2,y_2)=(4,6)

Let us plug the value in Equation (1)

(\frac{-2+4}{2} ),(\frac{-2+6}{2})

(\frac{2}{2}),(\frac{4}{2})\\ \\(1,2)

So, the midpoint of points (-2,-2)\ and\ (4,6) is (1,2).

3 0
4 years ago
Consider the quadratic equation below. 4x^2-5=3x+4 Determine the correct set-up for solving the equation using the quadratic for
Kipish [7]
4x²-5=3x+4
4x²-3x-9=0

x=(3±√((-3)²-4*4*-9))/2*4

x=3±√(9+144) /8

x=(3±√153) /8

x=⅜±√153/8
4 0
3 years ago
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