Normalizing the bounds,
y=186, z = (186-200)/12 = -1.17
y = 210, z = (210 - 200)/12 = 0.83
We want the area of the standard normal between those. Looking it up in the cumulative table,
Ф(1.17) = 0.87900
Ф(0.83) = 0.79673
We need Ф(-1.17) which is 1 - Ф(1.17)
Then the probability we seek is
p = Ф(0.83) - Ф(-1.17) = Ф(0.83) + Ф(1.17) - 1 = 0.87900 + 0.79673 - 1 = 0.67573
Answer: 67.6%
Answer:
c
Step-by-step explanation:
ive helped middle schoolers with this
The 82nd term for the sequence would be -4
∠A = 180° - (63°+101°)=16°
sine's rule
Answer:
The product of 8/3 and 6/5/is greater than 8/3.
Step-by-step explanation:
(8/3)*(6/5) = (8*6)/(3*5) = 48/15
16/5. = 3.2 and 8/3 = 2.7
