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jok3333 [9.3K]
3 years ago
7

The admission fee for a charity event is $7 for children and $10 for adults. The event was attended by 700 people, and the total

amount collected in admissions was $6,400.
There were
_children and
_adults at the show.
Mathematics
2 answers:
maria [59]3 years ago
6 0
If all were children, revenue would be 700*$7 = $4900. Revenue is actually $6400 -4900 = $1500 more than that. Each adult admission that replaces a child's admission adds $10 -7 = $3 to the revenue, so there must have been
  $1500/$3 = 500 . . . . adult admissions

There were 200 children at the show.
There were 500 adults at ths show.
Delicious77 [7]3 years ago
3 0
Hello!

You can make two expressions based on what you know

let x stand for the amount of children
let y stand for the amount of adults

x + y = 700
7x + 10y = 6400

You can multiply the first equation by 10 to be able to use elimination

10x + 10y = 700
7x + 10y = 6400

Subtract the two equations from each other

3x = 600

Divide both sides by 3

x = 200

Put x into one of the original equations to get y

200 + y = 700

Subtract 200 from both sides

y = 500

The answers are 200 children and 500 adults

Hope this helps!
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B)

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Step-1 : Multiply the coefficient of the first term by the constant <span> <span> 1</span> • -36 = -36</span> 

Step-2 : Find two factors of  -36  whose sum equals the coefficient of the middle term, which is  <span> -9 </span>.

<span><span>     -36   +   1   =   -35</span><span>     -18   +   2   =   -16</span><span>     -12   +   3   =   -9   That's it</span></span>


Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -12  and  3 
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Step-4 : Add up the first 2 terms, pulling out like factors :
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Final result :<span> (x + 3) • (x - 12)</span>
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