R = rides
S = sodas
6R + 3S = $21.75 —> -12R - 6S = -43.5
10R + 6S = $39.50–>10R + 6S = 39.5
Multiplying Justin’s whole equation by -2 will bring out the 6S’, so we can focus on the cost of one ride.
-2R = -4
Divide both sides by -2
So for one ride, it would cost $2.
To find the cost for one soda, we plug in the cost for a ride.
6(2) + 3S = $21.75
12 + 3S = $21.75
3S = $9.75
So for one soda, it would cost $3.25.
Step-by-step explanation:
We have,
Diameter of cylinder, d = 39.2 mm
Radius, r = 19.6 cm
Height of the cylinder, h = 39.2 mm
It is required to find the surface area of this cylinder. The formula of the surface area of cylinder is given by :
Putting all values we get :
Answer:
A. yes, the data represents a function because u have no repeating x values. A function cannot have repeating x values...they can have repeating y values, just not the x ones
Step-by-step explanation:
B. table : (8,8)(12,12)(14,16)(16,16)
look at ur points...when x = 8, y = 8...so the table, when x = 8 has a
value of 8
relation : f(x) = 8x - 5....when x = 8
f(8) = 8(8) - 5
f(8) = 64 - 5
f(8) = 59....and the relation has a value of 59
Therefore, the relation has a greater value when x = 8 <==
C. f(x) = 8x - 5...when f(x) = 19
19 = 8x - 5
19 + 5 = 8x
24 = 8x
24/8 = x
3 = x <==
60 = a * (-30)^2
a = 1/15
So y = (1/15)x^2
abc)
The derivative of this function is 2x/15. This is the slope of a tangent at that point.
If Linda lets go at some point along the parabola with coordinates (t, t^2 / 15), then she will travel along a line that was TANGENT to the parabola at that point.
Since that line has slope 2t/15, we can determine equation of line using point-slope formula:
y = m(x-x0) + y0
y = 2t/15 * (x - t) + (1/15)t^2
Plug in the x-coordinate "t" that was given for any point.
d)
We are looking for some x-coordinate "t" of a point on the parabola that holds the tangent line that passes through the dock at point (30, 30).
So, use our equation for a general tangent picked at point (t, t^2 / 15):
y = 2t/15 * (x - t) + (1/15)t^2
And plug in the condition that it must satisfy x=30, y=30.
30 = 2t/15 * (30 - t) + (1/15)t^2
t = 30 ± 2√15 = 8.79 or 51.21
The larger solution does in fact work for a tangent that passes through the dock, but it's not important for us because she would have to travel in reverse to get to the dock from that point.
So the only solution is she needs to let go x = 8.79 m east and y = 5.15 m north of the vertex.
Answer:
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
- Slope Formula:
Step-by-step explanation:
<u>Step 1: Define</u>
Point (4, 1.2)
Point (10, 6)
<u>Step 2: Find slope </u><em><u>m</u></em>
Simply plug in the 2 coordinates into the slope formula to find slope <em>m</em>
- Substitute [SF]:
- Subtract:
- Divide:
