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3 years ago

Keisha has a straightedge and a compass, but noprotractor. What kind of angle can Keisha draw exactly with only these tools?

1 answer:

5 0

Straight (it's a straight line!), full rotation (a circle), but nothing else since you can't measure the exact angle of it

You might be interested in

(a) Simplify the expression: (4x - 6) - (x + 5)

Liono4ka [1.6K]

Answer:

a) 3x - 11

b) 10x + 4

Step-by-step explanation:

a) The negative sign before the (x+5) means to subtract those values. Reverse the signs. Then combine like terms:

4x –6 –x –5. 4x–x–6–5

3x –11

b) Put all the x terms together.

Put all the integers together.

Add. Adding a negative is the same as subtracting.

4x+x+5x = 10x

+6-2 = 4

Combine them:

10x + 4

8 0

3 years ago

Analyze the diagram below and complete the instructions that follow.

Ratling [72]

Answer:

your answer is c

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Given the function f(x)= x^4 - 4x^3 -2, determine the absolute minimum value of ff on the closed interval [-2, 4].

kobusy [5.1K]

Answer:

Absolute Minimum: (3,−29)

Step-by-step explanation:

4 0

3 years ago

PLEASE HELP ME IT WOULD MEAN A LOT

arlik [135]

Answer:

12x³ - 3x

Step-by-step explanation:

Given 

f(x) = x and g(x) = 4x² - 1

Now, 

3 f(x) * g(x) 

= 3 * x (4x² - 1)

= 3x ( 4x² - 1 )

= 12x³ - 3x 

Hope it will help :)

4 0

3 years ago

HURRYYYYYYYYY!! What is the equation of the quadratic function with a vertex at (2, 25) and an x-intercept at (7,0)?

tangare [24]

Answer:

$y=-(x-7)(x+3)$

which is none of the choices provided.

Are you sure the question is right or even the choices?

You can even write it as:

$y=-(x+3)(x-7)$ but this is still not a choice.

Step-by-step explanation:

The vertex form of a quadratic is $y=a(x-h)^2+k$ .

This is called vertex form because it gives you the vertex is $(h,k)$ .

We are given that $(h,k)=(2,25)$ which makes our equation:

$y=a(x-2)^2+25$ .

We can find the value of $a$ by plugging in the x-intercept (7,0) for $(x,y)$ into:

$y=a(x-2)^2+25$

$0=a(7-2)^2+25$

$0=a(5)^2+25$

Subtract 25 on both sides:

$-25=a(5)^2$

$-25=a(25)$

Divide both sides by 25:

$\frac{-25}{25}=a$

$-1=a$ .

So the equation for the quadratic is:

$y=-1(x-2)^2+25$

Let's put this into factored form since all the choices are in factored form.

This will require us to multiply the (x-2)(x-2) out:

$y=-1(x-2)(x-2)+25$

$y=-1(x^2-2x-2x+4)+25$

$y=-1(x^2-4x+4)+25$

$y=-x^2+4x-4+25$

$y=-x^2+4x+21$

Factor out -1:

$y=-(x^2-4x-21)$

WE need to find two numbers that multiply to be -21 and add to be -4:

$y=-(x-7)(x+3)$

8 0

3 years ago

Read 2 more answers