<u>Given</u>:
Let the two numbers be x and y.
Two numbers multiply to be -7 and add to be -6.
This can be written in equation as,
and

<u>Value of the two numbers:</u>
Let us determine the value of the two numbers using substitution method.
Substituting
in the equation
, we get;

Simplifying, we get;




Thus, the values of x are x = 1,-7
When x = 1 , the equation
becomes 
When x = -7, the equation
becomes 
Therefore, the two numbers are 1 and -7
Answer:
(x+9)^2 + (y+1)^2 = 100
Step-by-step explanation:
Since the question says diameter, we know the boundary in a circle. Therefore, we just need to find the center and radius.
The center is the midpoint of the two endpoints on a diameter.
Here, it is (-9, -1).
Therefore, the left part of the equation is (x- -9)^2 + (y - -1)^2 = (x+9)^2 + (y+1)^2.
The radius: sqrt(8^2 + 6^2) = 10
So the equation is (x+9)^2 + (y+1)^2 = 100

It is true only whenever x tends to 0(zero)
it is not importent that x be in radian or in degree.