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3 years ago

Whats the reason for 8x-5-2x=2x+1-2x

1 answer:

4 0

Your answer is X= -1
you have to move terms first to get this
8x-5=2x+1
then collect like terms and calculate sum
8x-2x=1+5
lastly you divide both sides by 6
X=1
HOPE THIS HELPS! :)

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Can i have help please NO LINKS!!

seropon [69]

Answer: 115 miles

Step-by-step explanation:

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3 0

2 years ago

Read 2 more answers

URGENT! 40 POINTS! PLEASE HELP!

umka2103 [35]

Answer:

(a) $8 x(5 x-6)=40 x^{2}-48 x$

Step-by-step explanation:

(a) To find verify the answer we need to multiplying the equation $8 x(5 x-6)$

$8 x(5 x-6)=40 x^{2}-48 x$

Thus, this statement is true.

(b) To find verify the answer we need to multiplying the equation $-4 x\left(2 x^{2}+1\right)$

$-4 x\left(2 x^{2}+1\right)=-8 x^{3}-4 x$

Hence, the given statement is false.

$\begin{aligned}(x-3)(5 x-6) &=5 x^{2}-6 x-15 x+18 \\&=5 x^{2}-21 x+18\end{aligned}$

Hence, the given statement is true.

(d) To find verify the answer we need to multiplying the equation $(2 x+3)\left(x^{2}+3 x-5\right)$

$\begin{aligned}=(2 x+3)\left(x^{2}+3 x-5\right) &=2 x^{3}+6 x^{2}-10 x+3 x^{2}+9 x-15 \\&=2 x^{3}+9 x^{2}-x-15\end{aligned}$

Hence, the given statement is false.

4 0

2 years ago

Read 2 more answers

Use F = (9/5)C + 32 to convert 100°C to Fahrenheit

pshichka [43]

$\huge\fbox{Answer ☘}$

$\bold\blue{°F = ( \frac{9}{5} )°C \: + 32 }\\\\ °F = ( \frac{9}{5} )100° \: + \: 32 \\\\ °F = 9(20)° + 32 \\\\ °F= 180 + 32 \\\\ \bold{°F = 212°}$

hope helpful~

5 0

2 years ago

Suppose you were to draw all possible samples of size 36 from a large population with a mean of 650 and a standard deviation of

Lady_Fox [76]

Answer:

By the Central Limit Theorem, it is approximately normal with mean 650 and standard deviation 4.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .