Answer:
Pr(all will survive in one year) = 0.35 to 2 decimal places
Pr(at least 8 will survive) = 0.39 to 2 decimal places.
Step-by-step explanation:
Probability of a tree surviving one year is 0.9. While not surviving probability is 1 - 0.9 = 0.1
This is obtained from the 90℅ surviving rate for one year planted by the landscaping firm.
Probability that if 10 trees are planted, all will survive for one year is:
0.9x0.9x0.9x0.9x0.9x0.9x0.9x0.9x0.9x0.9 = 0.9^10 = 0.349
Probability that at least 8 will survive in one year can be expressed as
8 survived x 2 not survived +(or) 9 survived x 1 not survived +(or) 10 survived
= [(0.9^8)x(0.1^2) + (0.9^9)x(0.1^1) + (0.9^10)] = 0.391
Answer:
192 children and 145 adults were admitted.
Step-by-step explanation:
Let c represent the amount of children and let a represent the amount of adults.
Total fees for children = (Fee for one child) x (Amount of children) = 6.5c
Total fees for adults = (Fee for one adult) x (Amount of adults) = 15a
Total fees = Total fees for children + Total fees for adults
3423 = 6.5c +15a
We know that the amount of people who entered the park was 337. Therefore a+c=337, which means a=337-c.
Sub this in to the equation above to get:
3423 = 6.5c +15 (337-c)
3423 = 6.5c + 5055 - 15c
-1632 = -8.5c
c = 192
So there were 192 children.
Since a=337-c and c=192, a=337-192=145. So there were 145 adults.
To find the amount of feet in 4 miles you will need to take the amount of feet in 1 mile and multiply that by 4 to receive your answer hope this helps. 5280(feet per mile)*4=21120
Answer:
itself was just<em><u> </u></em><em><u>an</u></em><em><u> </u></em><em><u>awesome</u></em><em><u> </u></em><em><u>game</u></em><em><u> </u></em><em><u>that</u></em><em><u> </u></em><em><u>had</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>game</u></em><em><u> </u></em><em><u>in</u></em><em><u> </u></em><em><u>one</u></em><em><u> </u></em><em><u>game</u></em><em><u> </u></em><em><u>for</u></em><em><u> </u></em><em><u>my</u></em><em><u> </u></em><em><u>friends</u></em><em><u>.</u></em>
Answer:
We have, 2x+y=3 .......(1)
xy=1....(2)
In equation (2), we get
y=
x
1
..........(3)
y put in the equation (1)
2x+
x
1
=3
2x
2
+1=3x
2x
2
−3x+1=0
2x
2
−3x−1x+1=0
2x(x−1)−1(x−1)=0
x=1, x=
2
1
We take the value of x=1
x value put in equation (1)
2(1)+y=3
y=3−2
y=1
x=1
x and y value put (x+y)
x−y
=(1+1)
(1−1)
=2
0
=1
Hence, this is the answer
Was this answer helpful?
