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Anna007 [38]
3 years ago
8

How to find the limit of that question

Mathematics
1 answer:
jeka943 years ago
5 0
Factor the numerator using difference of cubes:
a^3 - b^3 = (a-b)(a^2 +ab+b^2)
a = x
b = 2

\frac{x^3 - 8}{x-2} = \frac{(x-2)(x^2 +2x+4)}{x-2} = x^2 +2x+4

Now you can evaluate limit as x=2.
\lim_{x \to 2} (x^2 +2x+4) = 2^2 +2(2)+4 = 12
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The answer is 2 y2 -9
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Solve this equation 3x + 5 = 7x – 7
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Read 2 more answers
If f(1) = 2 and f(n) = –2f(n − 1) then find the value of f(5).
dybincka [34]

Answer: 2f

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6 0
2 years ago
If a can is 20cm Haigh X 8cm diameter what is the volume
sattari [20]
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7 0
3 years ago
-3/7, -8/3 and -5/2,-2 slope
Alja [10]
So the points are (-3/7,-8/3) and (-5/2,-2)
to find the slope do
(y2-y1)/(x2-x1)
(x,y)
x1=-3/7
y1=-8/3
x2=-5/2
y2=-2

subsitute
\frac{-2-( \frac{-8}{3} )}{ \frac{-5}{2} - \frac{-3}{7} }
simplify by finding similar denomenators
\frac{\frac{-6}{3}-( \frac{-8}{3} )}{ \frac{-35}{14} - \frac{-6}{14} }
\frac{\frac{-6}{3}( \frac{8}{3} )}{ \frac{-35}{14} + \frac{6}{14} }
add
\frac{\frac{2}{3}}{ \frac{-29}{14}}
multiply top and bottom by \frac{-14}{29
\frac{\frac{-28}{87}}{1}
\frac{-28}{87}
answer is
slope=\frac{-28}{87}


8 0
3 years ago
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