Hello!
<h3><em><u>Answer</u></em></h3>
The area of the right triangle is 30 
. The perimeter is 40 in.
<h3><em><u>Explanation</u></em></h3>
First, we must find the measure of the hypotenuse of the triangle by using the Pythagorean Theorem.
+ 
64 + 225 = 
√289 =
17 = 
Now that we have all the side lengths, we can use the formulas to find the area and perimeter.
<h3>AREA:</h3>
A = 
A = (15 × 8) ÷ 2
A = 30
<h3>PERIMETER:</h3>
P = a + b + c
P = 8 + 15 + 17
P = 40
D=rt
So you're going to plug in the values listed: r= 9 1/2 and t=1 3/4
This will give you:
d=(9.5)(1.75)
Then you solve:
d=16.625
You should probably convert that decimal answer into a fraction since you're question gave it to you as a fraction.
This gives you three simultaneous equations:
6 = a + c
7 = 4a + c
1 = c
<u>c = 1
</u><u /><u />
If c =1,
6 = a + 1
<u>a = 5
</u><u /><u />
This doesn't work in the second equation, so the quadratic that goes through these points is not in the form y = ax^2 + bx + c
Was there supposed to be a b in the equation?
