Answer:
$12.43
Step-by-step explanation:
Given :
Mean = $8.52
Standard deviation, = $2.38
Stock price which falls beyond 0.05 of the distribution is at the 95th percentile
The 95th percentile distribution has a Pvalue of 1.645 (standard normal table)
We obtain the value of x, with z = 1.645
Using the Zscore relation :
Zscore = (score - mean) / standard deviation
1.645 = (score - 8.52) / 2.38
Cross multiply :
1.645 * 2.38 = score - 8.52
3.9151 = score - 8.52
Score = 8.52 + 3.9151
Score = $12.4351
Stock price beyond 0.05 is $12.43
Answer:
12
Step-by-step explanation:
I am pretty sure this is the answer. If it is correct i can give the explanation
Answer:
0.74 to 6.06
Step-by-step explanation:
The groups are independnet,
SE(xh bar-xa bar)=sqrt [sh^2/nh+sa^2/na]=sqrt [10.1^2/80+10.3^2/80]=1.61
At df=157, the t critical is 1.65
90%c.i=(xh bar-xa bar)+-tcritical SE(xh bar-xa bar)
=(25.2-21.8)+-1.65*1.61
=0.74 to 6.06
Answer:
sure why not
Step-by-step explanation:
