Answer:
V = 42.6 L
Explanation:
Given data:
Number of moles of Cl₂ = 1.9 mol
Temperature and pressure = standard
Volume occupy = ?
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
By putting values,
1 atm × V = 1.9 mol ×0.0821 atm.L /mol.K × 273.15 k
V = 42.6 atm.L / 1 atm
V = 42.6 L
6.5 moles of AgCl can be formed from 6.5 moles of Ag.
STOICHIOMETRY:
According to this question, silver reacts with hydrochloric acid to form silver chloride and hydrogen gas as follows:
2Ag + 2HCl → 2AgCl + H2
Based on this balanced equation, 2 moles of silver (Ag) produces 2 moles of silver chloride (AgCl).
This means that 6.5 moles of Ag will produce (6.5 × 2)/2 = 6.5 moles of AgCl.
Learn more about stoichiometry at: brainly.com/question/9743981?referrer=searchResults
Answer:
The answer in °C is 3498.85°C
Explanation:
The Celsius scale is considered a derived scale, defined in relation to the Kelvin scale.
The zero on the Celsius scale is defined as 273.15 K. This means that 100°C is defined as the equivalent of 373.15 K.
The Celsius scale is of intervals but not of proportions, which means that it pursues a relative scale and not an absolute scale.
To calculate the temperature in °C at which the tin becomes superconducting we will use the following formula:
°C = Temperature in K - 273.15 = 3772 - 273.15 = 3498.85°C
Answer:
1-(tert-butoxy)-2-methylpropane
Note: there is a mistake in formula, the correct formula is (CH₃)₂-CH-CH₂-O-C(CH₃)₃ not (CH₃)₂-CH-CH₂-O(CH₃)₃, because oxygen is a divalent compound.
Explanation:
<em>Structural formula is attached</em>
IUPAC naming rules
1. start numbering the chain from the functional group. In this compound we start from oxygen side.
2. Here we can see that at position 1 there is an oxy group along with a tertiary carbon having three methyl groups. So we write it as 1-tert-butoxy. Which means that there is a methoxy group at position 1 along with a tertiary carbon.
3. At position 2 we can see that there is a methyl group attached to the main chain, so we write it as 2-methyl.
4. Now we count the total number of carbons in the main chain. As we can see that there are 3 carbons in the remaining or parent chain, so we write it as propane
5. So the IUPAC name of the compound will be 1-(tert-butoxy)-2-methylpropane