Answer:

Explanation:
To convert from moles to grams, we must use the molar mass (also known as the gram formula mass).
First, look up the molar masses of the elements in the formula.
- C: 12.011 g/mol
- H: 1.008 g/mol
- O: 15.999 g/mol
Next, multiply by the subscript, because it tells us the number of atoms of each element in the formula.
- C₉: 4(12.011 g/mol)= 108.099 g/mol
- H₈: 8(1.008 g/mol)= 8.064 g/mol
- O₄: 4(15.999 g/mol)= 63.996 g/mol
Add the values.
- 108.099 + 8.064+63.996=180.159 g/mol
Use this molar mass as a ratio.

Multiply by the given number of moles, 0.40

The units moles of aspirin cancel.


The original number of moles has 2 sig figs (4 and 0), so answer must have the same. For the number we calculated, it is the ones place. The 0 in the tenth place tells us to leave the 2.

Answer:
If an atom has the same number of electrons as protons, it is a neutral atom.
Explanation:
Answer:


Explanation:
Hello,
In this case, since the nowadays concentration of CO2 is 414.51 ppm and the concentration in 1958 was 315.71 ppm, the total increase is computed via the difference between them:

Moreover, the average increase per year is computed considering that from 1958 to 2020, 62 years have passed, therefore, such average is:

Regards.
Answer:
The empirical formula of the hydrocarbon is CH.
Explanation:
The following data were obtained from the question:
Mass of hydrocarbon = 2.9 mg
Mass of CO2 = 9.803 mg
Mass of H2O = 2.006 mg
Next, we shall determine the mass of carbon (C) and hydrogen (H) in the compound since hydrocarbon contains carbon and hydrogen only.
This is illustrated below:
Molar mass of CO2 = 12 + (16x2) = 12 + 32 = 44 g/mol
Mass of CO2 = 9.803 mg
Mass of C in the compound =?
Mass of C in the compound =
12/44 x 9.803
= 2.674 mg
Molar mass of H2O = (2x1) + 16 = 2 + 16 = 18 g/mol
Mass of H2O = 2.006 mg
Mass of H in the compound =
2/18 x 2.006
= 0.223 mg
Finally, we shall determine the empirical formula of the hydrocarbon as follow:
Carbon (C) = 2.674 mg
Hydrogen (H) = 0.223 mg
Divide by their molar mass
C = 2.674 /12 = 0.223
H = 0.223 / 1 = 0.223
Divide both side by the the smallest
C = 0.223/0.223 = 1
H = 0.223/0.223 = 1
Therefore, the empirical formula of the hydrocarbon is CH.
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