The answer would be like that:
P1 V1 T2 = P2 V2 T1
V1 = ( P2 V2 T1)/(P1 T2)
The software rendering this question really butchered it... I think it's saying the displacement vector for the particle is
Differentiate twice with respect to time to get the velocity and acceleration vectors, respectively:
Then at , the acceleration of the particle is
which most closely resembles the first choice.
Answer:
10.82 m
Step-by-step explanation:
Length of ladder (L) = 15.5 m
Degree with the horizontal (θ) = 44°15'=44.25°
This problem can be interpreted as a right triangle with L being the hypotenuse. The distance 'd' the ladder goes up the wall is the side opposite to the given angle. Therefore, the sine property can be used to find 'd':
The distance that the ladder goes up the wall is roughly 10.82 m.
Answer:
69cm squared
Step-by-step explanation:
Area of the rectangle: 8*6= 48
Area of the semicircle: 1/2*6*3=9
Area of triangle: (12-8)*6*1/2=
4*6= 24
24*1/2=12
Area of figure: 48+9+12=69