Let us find the co ordinates of each vertex of the triangle .
Vertex A ( in firs second quadrant) = ( -5 ,3)
vertex B in third quadrant = ( -5, -5)
vertex C in fourth quadrant = ( 4, -2)
let us use distance formula AB^2 = ( -5 - 3)^2 + (-5 - -5 )^2 = 64 + 0
AB= 8
BC^2 = ( -2 - -5 )^2 + ( 4 - - 5)^2 = 9 + 81 = 90
BC = 9.48
AC^2 = ( -2 -3)^2 +( 4- -5)^2 = 25 + 81 = 106
AC= 10.29
Perimeter = sum of length of AB+ BC+ Ac = 8 + 10.29 + 9.48= 22.77
Answer:
there are going to be three zeros.
x=-1
x=-6
x=5
1:2 heads 4:6 less than 5 so 4:12
Answer:
Step-by-step explanation:
If we look at the picture,we can see that n<22
So the correct answer will be 22
4³ x 4^-6 you have to add the exponents, so it is <u>4 to the power of -3. </u> Hope this helps!
