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tankabanditka [31]
2 years ago
12

Okay please help find the value of x, measure of NE, measure of MD.

Mathematics
1 answer:
JulsSmile [24]2 years ago
5 0

Step-by-step explanation:

I need more information

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A boat travels 45 miles east (right) then 60 miles north (up), how far is it from the starting point?​
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A boat travels 45 miles east then 60 miles north, how far is it from where it started. Draw this. The hypotenuse of the right triangle is the square root (45^2)+(60^2)=square root of 2025=3600=square root of 5625, or 75 miles.

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3 years ago
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Can someone please help me.
Katena32 [7]
Given 
- f(n) values for n=1,2,3,4
- possible candidates for the function

Solution:
Method: Evaluate some of the values, for each function.  A function with ANY value not matching the given f(n) values will be rejected.

N=1, f(n)=4
f(1)=4-3(1-1)=4
f(1)=4+3^(1+1)=4+3^2=4+9=13 &ne; 4   [rejected]
f(1)=4(3^(n-1))=4(3^0)=4
f(1)=3(4^(n-1))=3(4^0)=3*1=3  [rejected]

N=2, f(n)=12
f(1)=4-3(2-1)=4-3(1)=1 &ne; 12   [rejected]
[rejected]
f(1)=4(3^(2-1)=4*3^1=4*3=12
[rejected]

Will need to check one more to be sure
N=3, f(n)=3
[rejected]
[rejected]
f(3)=4(3^(n-1))=4(3^(3-1))=4(3^2)=4*9=36   [Good]
[rejected]

Solution: f(n)=4(3^(n-1))










6 0
3 years ago
A production process produces 2% defective parts. a sample of 5 parts from the production is selected. what is the probability t
Lana71 [14]

Answer:

Probability of a sample that contains exactly two defective parts is .0037 or .37%

Step-by-step explanation:

As we know if P is the probability of achieving k results in n trials then probability formula is P = \binom{n}{k}p^{K}q^{n-k}

In this formula n = number of trials

                        k = number of success

                        (n-k) = number of failures

                         p = probability of success in one trial

                         q = (1-p) = probability of failure in one trial

In this sum n = 5

                  k = 2

number failures (n-k) = (5-2) = 3

                            p = 2% which can be written as .02

                            q = 98% Which can be written as .98

Now putting these values in the formula

                        P = \binom{5}{2}(.02)^{2}(.98)^{5-2}

                        P = \binom{5}{2}(.02)^{2}(.98)^{3}

                   \binom{5}{2}= 5!/3!2!    

                                              = 5×4×3×2×1/3×2×1×2×1

                                              = 5×2 =10

                                       P = 10×(.02)²×(.98)³

                                          = .0037 or .37%

4 0
3 years ago
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