Answer:
The dynamic viscosity of the liquid is 0.727 kg/m*s
Explanation:
In the equation for that viscosimeter, ν = KR⁴t, <u>the terms K and R are not dependent on the liquid that is being tested</u>, unlike ν and t.
Using that equation and the data given in the problem, we can calculate the product of K and R⁴.
1.19*10⁻³m²/s = (KR⁴)* 1430 s
KR⁴=8,32*10⁻⁷m²/s²
We can now calculate the<em> </em><u><em>kinematic</em></u> viscosity of the unknown liquid.
ν=8,32*10⁻⁷m²/s²*900s
ν=7.49*10⁻⁴m²/s
The relationship between the <em>kinematic</em> viscosity and the <em>dynamic</em> viscosity is given by the equation μ=ν * ρ, where μ is the dynamic viscosity and ρ is the density. Thus:
μ=7.49*10⁻⁴m²/s * 970 kg/m³
μ=0.727 kg/m*s
Answer:
The structure is shown below.
Explanation:
To draw a structure first we need to know its molecular formula, which is C2H6SO for dimethyl sulfoxide. The central atom is sulfur, which is bonded to an oxygen and with two methyl groups (CH3).
Sulfur has 6 electrons in its valence shell, as so oxygen. To complete the octet of oxygen, 2 electrons will be shared by sulfur with it. So, it remains 4 electrons at the central atom. Carbon has 4 electrons in its valence shell, so it needs more 4 to be stable, and is already sharing 3 electrons with the hydrogens, thus, sulfur will share one electron with each one of them.
So, it will remain 2 nonbonding electrons in the central atom. According to the VSPER theory, to minimize formal charges, the structure would be a trigonal pyramid, but, the double bonding with oxygen has a large volume, then the geometry will be trigonal, as shown below.
Answer:
59.30% I
Explanation:
mi respuesta es esa porque es la más sercana