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Bas_tet [7]
3 years ago
5

Match each term with the correct location on a trophic pyramid.

Chemistry
1 answer:
zubka84 [21]3 years ago
6 0

Answer:

I think it's C

hope this helps

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What would you expect to happen if you raised the temperature of the water to 85°C? Check all that apply.
Mumz [18]
I don't know your options but maybe this bit of information will help, the boiling point of water is 212<span>°</span>F so at that temperature it will likely just start evaporating 
5 0
3 years ago
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If you have 2 Moles of C3H6 and 10 Moles of O2, which reactant is limiting the following reaction: 2C3H6 + 9O2 → 6CO2 + 6H2O?
Hatshy [7]

Answer:

The limiting reactant is propene, C_3H_6.

Explanation:

2C_3H_6 + 9O_2 \rightarrow 6CO_2 + 6H_2O

Moles of nitrogen propene  = 2 mol

Moles of oxygen  = 10 mol

According to reaction, 2 moles of propene reacts with 9 moles of oxygen gas, then 2 moles of propene will react with:

=\frac{9}{2}\times 2mol=9\text{mol of oxygen gas}

According to the question, we have 10 moles of oxygen gas, which is more than 9 moles of oxygen gas. This indicates that propene is present in a limiting amount hence, it is a limiting reactant.

The limiting reactant is propene, hence the correct answer is the C_3H_6.

5 0
3 years ago
How do the rates of the forward and reverse reactions change throughout a reaction?
fenix001 [56]
The rates of the forward and reverse reaction depends on the temperature on which the reaction will proceed, either endothermic of exothermic. it also depends of the concentration of the reactants and products. if the reaction is exothermic, so if the reaction temperature is increased then it will favor the forward reaction, then if the reaction is lowered then it will favor the reverse reaction
3 0
3 years ago
A pure substance is matter that consists of matter with a composition that
sashaice [31]
Is constant (matter that has a composition that is the same everywhere)
7 0
3 years ago
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A solution is made by dissolving
AVprozaik [17]

Answer:

0.342 m

Explanation:

From the question given above, the following data were obtained:

Mass of NaBr = 14.57 g

Mass of water = 415 g

Molar mass of NaBr = 102.89 g/mol

Molality of NaBr =?

Next, we shall determine the number of mole in 14.57 g of NaBr. This can be obtained as follow:

Mass of NaBr = 14.57 g

Molar mass of NaBr = 102.89 g/mol

Mole of NaBr =?

Mole = mass / molar mass

Mole of NaBr = 14.57 / 102.89

Mole of NaBr = 0.142 mole

Next, we shall convert 415 g of water to kg. This can be obtained as follow:

1000 g = 1 Kg

Therefore,

415 g = 415 g × 1 Kg / 1000 g

415 g = 0.415 Kg

Thus, 415 g is equivalent to 0.415 Kg.

Finally, we shall determine Molality of the solution as follow:

Mole of NaBr = 0.142 mole

Mass of water = 0.415 Kg

Molality of NaBr =?

Molality = mole / mass of water in Kg

Molality of NaBr = 0.142 / 0.415

Molality of NaBr = 0.342 m

Therefore, the molality of NaBr solution is 0.342 m.

5 0
3 years ago
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