4.648 gm of solute is needed to make 37.5 mL of 0.750 M KI solution.
Solution:
We will start with the Molarity
Also we know 1000 ml = 1 L
Therefore 37.5 ml by 1000ml we obtained 0.0375L
Equation for solving mole of solute
Now, multiply 0.750M by 0.0375
Substitute the known values in the above equation we get
Also we know that Molar mass of KI is 166 g/mol
So divide the molar mass value to get the no of grams.
So 4.648 gm of Solute is required for make 37.5 mL of 0.750 M KI solution.
There is 213 units i believe hope so
Answer:
We can do an experiment with vinegar to see what happens to the calcium in an eggshell when it is exposed to an acid.
Answer is: the temperature is 28.9°C.
n = 2.48; amount of the gas.
V = 30.0 L; volume of the gas.
p = 1559 mmHg ÷ 760 mmHg/atm.
p = 2.05 atm; pressure of the gas.
R = 0.0821 L·atm/mol·K.
Ideal gas law: p·V = n·R·T.
T = p·V ÷ (n·R).
T = 302.05 K - 273.15.
T = 28.9°C; temperature of the gas.
Answer:
<em><u>1</u></em> C10H16 + <em><u>8</u></em> Cl2 --> <em><u>10</u></em> C + <em><u>16</u></em> HCl
