It will take 24 minutes.
this is because the lowest common multiple is 24.
hope this helps you
Answer: - 0.28
Explanation:
1) Expected value: is the weighted average of the values, being the probabilities the weight.
That is: ∑ of prbability of event i × value of event i.
In this case: (probability of getting 2 or 12) × (+6) + (probability of gettin 3 or 11) × (+2) + (probability of any other sum) × (-1).
2) Sample space:
Sum Points awarded
1+ 1 = 2 +6
1 + 2 = 3 +2
1 + 3 = 4 -1
1 + 4 = 5 -1
1 + 5 = 6 -1
1 + 6 = 7 -1
2 + 1 = 3 +2
2 + 2 = 4 -1
2 + 3 = 5 -1
2 + 4 = 6 -1
2 + 5 = 7 -1
2 + 6 = 8 -1
3 + 1 = 4 -1
3 + 2 = 5 -1
3 + 3 = 6 -1
3 + 4 = 7 -1
3 + 5 = 8 -1
3 + 6 = 9 -1
4 + 1 = 5 -1
4 + 2 = 6 -1
4 + 3 = 7 -1
4 + 4 = 8 -1
4 + 5 = 9 -1
4 + 6 = 10 -1
5 + 1 = 6 -1
5 + 2 = 7 -1
5 + 3 = 8 -1
5 + 4 = 9 -1
5 + 5 = 10 -1
5 + 6 = 11 +2
6 + 1 = 7 -1
6 + 2 = 8 -1
6 + 3 = 9 -1
6 + 4 = 10 -1
6 + 5 = 11 +2
6 + 6 = 12 +6
2) Probabilities
From that, there is:
- 2/36 probabilities to earn + 6 points.
- 4/36 probabilites to earn + 2 points
- the rest, 30/36 probabilities to earn - 1 points
3) Expected value = (2/36)(+6) + (4/36) (+2) + (30/36) (-1) = - 0.28
Answer:
Time taken by the un powered raft to cover this distance is T = 192.12 hr
Step-by-step explanation:
Let speed of boat = u 
Speed of current = v
Let distance between A & B = 100 km
Time taken in downstream = 32 hours
u + v = 3.125 ------ (1)
Time taken in upstream = 48 hours
u - v = 2.084 ------- (2)
By solving equation (1) & (2)
u = 2.6045
v = 0.5205
Now the time taken by the un powered raft to cover this distance
Because un powered raft travel with the speed of the current.
T = 192.12 hr
Therefore the time taken by the un powered raft to cover this distance is
T = 192.12 hr
Answer:
d(3d-10)
Step-by-step explanation:
You pull out the common factor of d from both terms, and group the remaining terms inside a parenthesis.
Linear, because the graph of the line is just a straight line without any curves, and the power of x is 1. If x was raised to the second, third, fourth, etc. power, it would be a nonlinear equation.
